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HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Haryana State Board HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry Important Questions and Answers.

Haryana Board 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Short/Long Answer Type Questions

Question 1.
The distance between the point A(5, -3) and B(13, m) is 10 units. Calculate the value of m.
Solution :
Here, x1 = 5, y1 = – 3, x2 = 13, y2 = m
Distance (AB) = 10
⇒ \(\sqrt{(13-5)^2+(m+3)^2}\) = 10
⇒ \(\sqrt{8^2+m^2+9+6 m}\) = 10
⇒ \(\sqrt{64+m^2+9+6 m}\) = 10
⇒ \(\sqrt{73+m^2+6 m}\) = 10
⇒ [Squaring both sides]
⇒ m2 + 6m + 73 – 100 = 0
⇒ m2 + 6m – 27 = 0
⇒ m2 + (9m – 3m) – 27 = 0
⇒ m2 + 9m – 3m – 27 = 0
⇒ m(m + 9) – 3(m + 9) = 0
⇒ (m + 9) (m – 3) = 0
⇒ m + 9 = 0 or m – 3 = 0
⇒ m = – 9 or m = 3

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 2.
If the distances of P(x, y) from A(5, 1) and B(-1, 5) are equal, then prove that 3x
Solution :
Since, of from A(5, 1) and B(-1, 5) are equal
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 1
So, PA = PB
⇒ PA2 = PB2
⇒ (5 – x)2 + (1 – y)2 = (-1 – x)2 + (5 – y)2
⇒ 25 + x2 – 10x + 1 + y2 – 2y = 1 + x2 + 2x + 25 + y2 – 10y
⇒ 26 – 10x – 2y = 26 + 2x – 10y
⇒ – 10x – 2x = – 10y + 2y
⇒ – 12x = – 8y
⇒ 3x = 2y Hence proved.

Question 3.
It k(5, 4) is the mid point of line segment PQ and coordinates of Q are (2, 3) then find the coordinates of point P.
Solution :
Let coordinate of point P be (x, y)
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 2
Since k(5, 4) is mid point of P(x, y) and Q(2, 3)
∴ 5 = \(\frac{x+2}{2}\) and 4 = \(\frac{y+3}{2}\)
⇒ 10 = x + 2 and 8 = y + 3
⇒ x = 10 – 2 and y = 8 – 3
⇒ x = 8 and y = 5
∴ coordinates of point P are (8, 5)

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 4.
If the midpoint of two points A(2, 5) and B(-5, y) is (-\(\frac {7}{2}\), 3). then find the distance between points A and B.
Solution :
Let point C(-\(\frac {7}{2}\), 3) is the midpoint of line AB.
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 3
∴ 3 = \(\frac{5+y}{2}\)
⇒ 6 = 5 + y
⇒ y = 6 – 5 = 1
Coordinates of point is (-5, 1)
Length of AB = \(\sqrt{(-5+2)^2+(1-5)^2}\)
= \(\sqrt{(-3)^2+(-4)^2}\)
= \(\sqrt{9+16}\) = \(\sqrt{25}\) = 5
Hence, length of AB = 5 units.

Question 5.
In a parallelogram ABCD A(3, 1), B(5, 1), C(a, b) and D(4, 3) are the vertices. Find vertex C(a, b).
Solution :
We know that diagonals of a parallelogram bisects each other so, O is the mid point of AC as well as that of BD
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 4
∴ Coordinates of mid point of AC = coordinates of mid point of BD
⇒ (\(\left(\frac{3+a}{2}, \frac{1+b}{2}\right)\)) = (\(\left(\frac{5+4}{2}, \frac{1+3}{2}\right)\))
⇒ (\(\left(\frac{3+a}{2}, \frac{1+b}{2}\right)\)) = (\(\frac {9}{2}\), \(\frac {4}{2}\))
⇒ \(\frac{3+a}{2}\) = \(\frac {9}{2}\) and \(\frac{1+b}{2}\) = \(\frac {4}{2}\)
⇒ 3 + a = 9 and l + b = 4
⇒ a = 9 – 3 and b = 4 – 1
⇒ a = 6 and b = 3
Hence, coordinates of vertex C is (6, 3)

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 6.
If the coordinates of two adjacent vertices of a parallelogram are (3, 2), (1, 0) and diagonals bisect each other at (2, – 5), find the coordinates of the other two vertices.
Solution :
Diagonals of a parallelogram bisect each other.
Let coordinates of vertices C be (x1, y1) and d be (x2, y2) O is the mid point of AC as well as that of BD.
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 5
∴ coordinates of mid point of AC = (2, – 5)
⇒ (\(\frac{3+x_1}{2}, \frac{2+y_1}{2}\)) = (2, – 5)
⇒ \(\frac{3+x_1}{2}\) = 2, \(\frac{2+y_1}{2}\) = – 5
⇒ 3 + x1 = 4, 2 + y1 = – 10
⇒ x1 = 1, y1 = – 12
And coordinates of mid point of BD = (2, – 5)
⇒ (\(\frac{1+x_2}{2}, \frac{0+y_2}{2}\)) = (2, – 5)
⇒ \(\frac{1+x_2}{2}\) = 2, \(\frac{0+y_2}{2}\) = – 5
⇒ 1 + x2 = 4, y2 = – 10
⇒ x2 = 3, y2 = – 10
Coordinates of vertice Care (1, -12) and vertice D are (3, – 10).

Question 7.
If the midpoint of the line segment joining the points A(3, 4) and B(k, 6) is P(x, y) and x + y – 10 = 0. Find the value of k.
Solution :
Since, mid point’s coordinates are C(x, y)
∴ x = \(\frac{3+k}{2}\) and y = \(\frac{4+6}{2}\) = 5
Since (x, y) lies the equation x + y – 10, so
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 6
substituting the value, A(3, 4) of x, y in this equ., we get
\(\frac{3+k}{2}\) + 5 – 10 = 0
⇒ \(\frac{3+k}{2}\) – 5=0
⇒ \(\frac{3+k-10}{2}\) = 0
⇒ k – 7 = 0
⇒ k = 7
Hence, value of k is 7.

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 8.
The coordinate of the vertices of ΔABC are A (7, 2), B (9, 10) and C(1, 4). If E and F are the mid points of AB and AC respectvely, prove that EF = \(\frac {1}{2}\)BC
Solution :
Since, E and f are the mid points of AB and AC respectvely coordinates of points are
\(\frac{9+7}{2}, \frac{10+2}{2}\) = (8, 6)
Coordinates of points Fare
\(\frac{1+7}{2}, \frac{4+2}{2}\) = (4, 3)
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 7

Question 9.
If the point C(-1, 2) divides in ternally the time segments joining A(2, 5) and B(x, y) in the ratio 3 : 4, find the coordinates of B.
Solution :
Hence, x1 = 2, y1 = 5, x2 = x, y2 = y, x = – 1, y = 2, m1 = 3, m2 = – 4
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 8
⇒ 3x + 8 = – 7 and 3y + 20 = 14
⇒ 3x = – 7 – 8 and 3y = 14 – 20
⇒ 3x = -15 and 3y = -6
⇒ x = –\(\frac {15}{3}\) and y = – \(\frac {6}{3}\)
⇒ x = – 5 and y = – 2
Hence, coordinate of point Bare (-5, -2)

Question 10.
In what ratio does the point P (\(\frac {24}{11}\), y) divide the line segment joining the points P(2, -2) and Q(3, 7) ? Also find the value y.
Solution :
Let the required ratio be k : 1
Here, x1 = 2, y = – 2, x2 = 3, y2 = 7, x = \(\frac {24}{11}\), y = y
m1 = k, m2 = 1
By section formula, we have
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 9

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 11.
Find the value of P, if the points A(2, 3) B(4, P) and C(6, – 3) are collinear.
Solution :
The given points are collinear So, the area of ΔABC will be zero.
Here, x1 = 2, y1 = 3, x2 = 4, y2 = P, x3 = 6, y3 = – 3
Area of ΔABC = 0
⇒ \(\frac {1}{2}\)[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)] = 0
⇒ \(\frac {1}{2}\)[2 (P + 3) + 4 (-3 – 3) + 6 (3 – P)]= 0
⇒ \(\frac {1}{2}\)[2P + 6 – 24 + 18 – 6P] = 0
⇒ \(\frac {1}{2}\)[-4P + 0] = 0
⇒ – 4P = 0
⇒ P = 0

Question 12.
Find the area of triangle ABC with A(1, – 4) and the mid points of sides through A being (2, – 1) and (0, – 1).
Solution :
Let the coordinates of vertices B be (x2, y2) and C be (x3, y3)
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 10
Let E (2, – 1) and f(0, – 1) are mid points of AB and AC respectively,
∴ 2 = \(\frac{1+x_2}{2}\) and – 1 = \(\frac{-4+y_2}{2}\)
⇒ 4 = 1 + x2 and – 2 = – 4 + y2
⇒ x2 = 3 and y2 = 2
∴ (x2, y2) = (3, 2)
Again 0 = \(\frac{1+x_3}{2}\) and – 1 = \(\frac{-4+y_2}{2}\)
⇒ 0 = 1 + x3 and – 2 = – 4 + y3
⇒ x3 = – 1 and y3 = 2
∴ (x3, y3) = (-1, 2)
Here, x1 = 1, y1 = – 4, x2 = 3, y2 = 2, x3 = -1, y3 = 2
Area of ABC
= \(\frac {1}{2}\)[x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2)]
= \(\frac {1}{2}\)[1(2 – 2) + 3 (2 + 4) + (-1)(-4 – 2)]
= \(\frac {1}{2}\)[1 × 0 + 3 × 6 + (-1) × (- 6)]
= \(\frac {1}{2}\)[0 + 18 + 6]
= \(\frac {1}{2}\) × 24 = 12
Hence, area of ABC = 12sq. units.

Question 13.
Prove that the points (2, -2), (2, 1) and (5, 2) are the vertices of a right angled triangle. Also find the area of this trian.
Solution :
Let the points A (2, -2), B (-2, 1) and C (5, 2) are the vertices of right angled triangle.
AB2 = (-2 – 2)2 + (1 + 2)2
= 16 + 9 = 25
BC2 = (5 + 2)2 + (2 – 1)2 = 49 + 1 = 50
And AC2 = (5 – 2)2 + (2 + 2)2
= 9 + 16 = 25
AB2 + AC2 = 25 + 25 = 50 = BC2
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 11
Since, BC2 = AB2 + AC2, So by converse of phythagores theorem ∠A = 90° there fore point A (2, -2), B (-2, 1) and C (5, 2) are the vertices of a right angled triangle
Here, x1 = 2, y1 = -2, x2 = -2, y2 = – 1, x3 = 5, y3 = 2
Area of ΔABC
= \(\frac {1}{2}\)[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= \(\frac {1}{2}\)[2(1 – 2) + (-2)(2 + 2) + 5(-2 – 1)]
= \(\frac {1}{2}\)[2 × (-1) + (-2) × 4 + 5 × (-3)]
= \(\frac {1}{2}\)[- 2 – 8 – 15]
= \(\frac {1}{2}\)[-25]
= \(\frac {-25}{2}\)
Hence, area of Δ = \(\frac {25}{2}\)sq. units.

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 14.
Find the area of that triangle whose vertices are (-3, -2), (5, -2) and (5, 4). Also prove that it is a right-angled triangle
Solution :
Let the points of vertices be A(-3, – 2), B (5, -2) and C (5, 4)
Here, x1 = – 3, y1 = – 2, x2 = 5, y2 = – 2, x3 = 5 and y3 = 4
Area of D ABC
= \(\frac {1}{2}\)[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= \(\frac {1}{2}\)[(-3)(-2 – 4) + 5 (4 + 2) + 5(-2 + 2)]
= \(\frac {1}{2}\)[(-3) × (-6) + 5 × 6 + 5 × 0)]
= \(\frac {1}{2}\)[18 + 30 + 0]
= \(\frac {1}{2}\) × 48 = 24 sq. units
AB2 = (5 + 3)2 + (-2 + 2)2 = 82 + 02 = 64
BC2 = (5 – 5)2 + (4 + 2)2 = 02 + 62 = 36
AC2 = (5 + 3)2 + (4 +2)2 = 82 + 62 = 64 + 36 = 100
AB2 + BC2 = 64 + 36 = 100 = AC2
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 12
By converse of phythagoras theorem ∠B = 90° Hence, ΔABC is a right angled triangle.

Question 15.
In a ΔABC, A is (1, – 4). If E (0, -1) and Δ(2,-1) are the mid points of AB and AC. Calculate the area of ΔABC.
Solution :
Let the coordinates of vertices B is (x2, y2) and C is (x3, y3) since, E is the mid point of AB
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 13
∴ 0 = \(\frac{1+x_2}{2}\) and – 1 = \(\frac{-4+y_2}{2}\)
⇒ 0 = \(\frac{1+x_2}{2}\) and – 2 = – 4 + y2
⇒ x2 = -1 and y2 = – 2 + 4 = 2
(x2, y2) = (-1, 2)
Since, D is the midpoint of AC
∴ 2 = \(\frac{1+x_3}{2}\) and – 1 = \(\frac{-4+y_2}{2}\)
⇒ 0 = 1 + x2 and – 2 = – 4 + y2
⇒ x2 = -1 and y2 = – 2 + 4 = 2
∴ (x3, y3) = (-1, 2)
Since, D is the midpoint of AC.
∴ 2 = \(\frac{1+x_3}{2}\) and – 1 = \(\frac{-4+y_3}{2}\)
4 = 1 + x3 and -2 = – 4 + y3
x3 = 3 and y3 = 4 – 2 = 2
∴ (x3, y3) = (3, 2)
Here, x1 = 1, y1 = – 4, x2 = – 1, y2 = 2, x3 = 3, y3 = 2
Area of ΔABC
= \(\frac {1}{2}\)[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= \(\frac {1}{2}\)[1(2 – 2) + (-1) (2 + 4) + 3(-4 – 2)]
= \(\frac {1}{2}\)[1 × 0 + (-1) × 6 + 3 × (-6)]
= \(\frac {1}{2}\)[0 – 6 – 18]
= \(\frac {1}{2}\) × (-24) = – 12
Hence, area of ΔABC = 12 sq. units.

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 16.
Find the area of the triangle formed by joining the mid points of the sides of a triangle, whose coordinates of vertices are (0, -1), (2, 1) and (0, 3).
Solution :
Let vertices of triangle be A (0, -1), B (2, 1) and (0, 3) in which of sides AB, BC and AC respectvely.
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 14
∴ Coordinates of point
(D) = \(\frac{1+0}{2}, \frac{1-1}{2}\) = (1, 0)
Coordinates of point
E = \(\frac{2+0}{2}, \frac{1+3}{2}\) = (1, 2)
And Coordinates of point
F = \(\frac{0+0}{2}, \frac{3-1}{2}\) = (0, 1)
Here, x1 = – 1, y1 = 0, x2 = 1, y2 = 2, x3 = 0, y3 = 1
Area of ΔDEF
= \(\frac {1}{2}\)[x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= \(\frac {1}{2}\)[1 (2 – 1) + 1(1 – 0) + 0 (0 – 2)]
= \(\frac {1}{2}\)[1 × 1 + 1 × 1 + 0]
= \(\frac {1}{2}\) × (1 + 1)
= \(\frac {1}{2}\) × 2 = 1 sq. unit.
Hence, area of ΔDEF = 1sq. unit.

Fill in the Blanks

Question 1.
The point of intersection of two axes is called ……….
Solution :
origin

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 2.
The distance of a point from the y axis is known its ………….
Solution :
abscissa

Question 3.
The ……… of a line segment divides the line segment in the ratio 1 : 1
Solution :
midpoint

Question 4.
If the area of a triangle is ……… sequare unit, then its vertices will be collinear.
Solution :
zero

Question 5.
The distance of a point from the x axis is called its …….
Solution :
ordinate

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 6.
The distance of a point P(x, y) from the ………. is \(\sqrt{x^2+y^2}\)
Solution :
origin.

Multiple Choice Questions

Question 1.
The coordinates of the point which is reflection of point (-3, 5) in x axis are :
(a) (3, 5)
(b) (3, -5)
(c) (-3, -5)
(d) (-3, 5)
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 15
Solution :
(d) (-3, 5)

In graph paper we observe reflection of (-3, 5) in axis is (-3, -5).

Question 2.
The point P on x axis equidistant from the A(-1, 0) and B(5, 0) is:
(a) (2, 0)
(b) (0, 2)
(c) (3, 0)
(d) (2, 2)
Solution :
(a) (2, 0)

Since point P on x axis. So the coordinates of P(x, 0)
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 16
∵ Point P is equidistant from point A and point B.
∴ PA = PB
⇒ PA2 = PB2
⇒ (-1 – x)2 + (0 – 0)2 = (5 – x)2 + (0 – 0)2
⇒ 1 + x2 + 2x + 0 = 25 + x2 – 10x + 0
⇒ x2 + 2x – x2 + 10x = 25 – 1
⇒ 12x = 24
⇒ x = \(\frac {24}{12}\) = 2
Coordinates of point P(2, 0).

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 3.
The distance between the points (acosθ + b sinθ, 0) and (0, asinθ – bcosθ), is :
(a) a2 + b2
(b) a2 – b2
(c) \(\sqrt{a^2+b^2}\)
(d) \(\sqrt{a^2-b^2}\)
Solution :
(c) \(\sqrt{a^2+b^2}\)

Let the given points A (a cosθ + b sinθ, 0) and (o, a sinθ – b cosθ)
The distance AB
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 17

Question 4.
If the point P(6, 2) divides the line segment joining A(6, 5) and B(4, y) in the ratio 3 : 1, then the value of y is:
(a) 4
(b) 3
(c) 2
(d) 1
Solution :
(d) 1

The point P(6, 2) divides the line segment joining A(6, 2) and B(4, y) in the ratio 3 : 1
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 18
Here x1 = 6, y1 = 5, x2 = 4, y2 = y, m1 = 3, m2 = 1, x = 6, y = 2
By section formula
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 19

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry

Question 5.
If the point P(k, 0) divides the line segment joining the points A(2, – 2) and B(-7, 4) in the ratio 1 : 2 then the value of k is :
(a) 1
(b) 2
(c) – 2
(d) – 1
Solution :
(d) – 1

Here, x1 = 2, y1 = – 2, x2 = – 7, y2 = 4, x = k, y = 0, m1 = 1, m2 = 2.
By section formula,
HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry - 20

Question 6.
The value of P, for which the points A(3, 1), B(5, P) and C (7, – 5) are collinear is :
(a) – 2
(b) 2
(c) – 1
(d) 1.
Solution :
(a) – 2

the given points are collinear. So, area of ΔABC is zero.
Here, x1 = 3, y1 = – 1, x2 = 5, y2 = P, x3 = 7, y3 = – 5
Area of ΔABC = 0
⇒ \(\frac {1}{2}\)[x1 (y2 – y3) + x2(y3 – y1) + x3(y1 – y2)] = 0
⇒ \(\frac {1}{2}\)[3(P + 5) + 5(-5 – 1) + 7(1 – P)] = 0
⇒ \(\frac {1}{2}\)[3P + 15 + 5(-6) + 7 – 7P] = 0
⇒ \(\frac {1}{2}\)[3P + 15 – 30 + 7 – 7P] = 0
⇒ \(\frac {1}{2}\)[-4P – 8] = 0
⇒ -4P = 8
⇒ P = \(\frac {8}{- 4}\)
⇒ P = – 2

HBSE 10th Class Maths Important Questions Chapter 7 Coordinate Geometry Read More »

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Haryana State Board HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts Important Questions and Answers.

Haryana Board 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 1.
Chemically, how can the elements found in nature be divided?
Answer:
1. In present times, 114 elements are known to us.
2. These elements combine in several ways and give rise to a very large number of compounds.
3. On the basis of their chemical properties aU the compounds can be added to three groups. They are:

  • Acids,
  • Bases and
  • Salts.

4. Thus, all the compounds of this world belong to one or the other group.
5. In this sense, a compound may be acidic, basic or a salt.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 2.
What is an acid?
Answer:
Acids: An acid is a compound having hydrogen which when dissolved in water releases ie. dissociates hydrogen ions (H+) (to be specific (H3O+ ions).
Example:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 1

Hydrochloric acid (HCl), sulphuric acid (H2SO4,) nitric acid (HNO3), etc. are all examples of acids.
(Note: Water H2O also has hydrogen in it but when you add water to water, it does not release hydrogen ions (H+). Hence, water is not acid. Similarly, NaOH has hydrogen but it does not release hydrogen ions (H+) when dissolved in water. NaOH is a base. So, only those substance which on dissolving to water release hydrogen ions (H+) are called acids.)

Testing of acid:
If you put acid on blue litmus paper, the blue litmus paper will turn red. This means the substance put is acid.

Question 3.
What is a base?
(a) Bases:
1. A base is a metal hydroxide substance which when dissolved in water release hydroxide (OH) ions. (Second definition: A metal hydroxide or a metal oxide substance when dissolved in acid produces salt and water and hence is called a base.)

2. Sodium hydroxide (NaOH), calcium hydroxide (Ca(OH)2, potassium hydroxide (KOH), Calcium oxide (CaO), etc. are bases
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 2

Testing of base:
If you put base on red litmus paper, the red litmus paper will turn blue. This means the substance put is base.

Question 4.
What is a salt?
Answer:
A salt is an ionic compound which is formed from the neutralization reaction of an acid and a base. Thus, we get salt when we react an acid with a base.
Note:
(1) When an acid and a base are mixed in right proportion, both acid and base lose their properties. In other words, they neutralize each other. Such a reaction is called neutralization reaction.
(2) When salt is dissolved in water it gets ionized into anions and cations)

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 5.
State two ways to test if the substance is acid.
Whether a substance is an acid or not can be tested with any of the given methods:
Answer:
1. Litmus paper: If you place a drop of a given substance on a moist litmus paper and it turns red, then the substance is acid.
2. Test with metals:  If you put metal in an aqueous substance and the reaction releases hydrogen gas then it means that the aqueous substance is acid.

Question 6.
What are olfactory indicators?
Answer:
1. Olfactory means ‘relating to the sense of smell’. Those substances whose smell changes in acidic or basic solutions are called olfactory indicators.
2. When an acid or a base is added to an olfactory substance, the characteristic smell of that substance cannot be detected.

Question 7.
How does onion and vanilla essence help in finding if a substance is acid or a base?
Answer:
1. If you add onion juice (or vanilla essence) to a base, the onion juice (or vanilla) will lose its smell. However, it will not lose the smell if added to acid.
2. Thus change in smell will help us to find out if the substance added to onion (or vanilla) is acidic or basic.

Question 8.
State three properties of acids and bases.
Answer:
Properties of acid:

  • Acids are sour in taste
  • They turn blue colour litmus paper into red
  • Acids react with base and form salt and water

Properties of bases:

  • Bases are bitter in taste
  • They change red litmus paper to blue
  • Bases react with acids to form salt and water

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 9.
What happens when an acid reacts with metal? Give one example.
Answer:
When acid reacts with metal, metallic salt of that metal and hydrogen gas are produced.
Acid + Metal →  Salt of Metal + Hydrogen gas
Example:
1. When zinc metal is added to sulphuric acid the reaction gives out zinc sulphate which is a salt and hydrogen gas.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 3

Question 10.
What happens when a base reacts with a metal? Give one example.
Answer:
When a strong base reacts with certain metals, it produces salt and hydrogen gas.
Base + Metal → Salt + Hydrogen gas
Example:
1. When sodium hydroxide (NaOH) reacts with certain metals like zinc Zn, salt and hydrogen gas are produced.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 4

Question 11.
When zinc metal is treated with dilute HCl or dilute H2SO4, hydrogen gas is evolved, but with dilute HNO3 hydrogen gas is not evolved. Explain.
Answer:
Zinc metals reacts with dilute HCl and dilute H2SO4 evolving hydrogen gas. Since Zn metal is more reactive than H2 gas, Zn can displace H2 gas from dilute HCl and dilute H2SO4 solutions.
Reaction:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 5
Hydrogen gas is not evolved by the reaction of Zn metal with dilute HNO3, because HNO3 is a strong oxidizing agent and H2 gas evolved during reaction is oxidized to H2O. Therefore, H2 gas is not obtained during the reaction of Zn with HNO3.

Question 12.
What happens when an acid reacts with metal carbonate or metal hydrogen carbonate? Give one example.
Answer:
Reaction of acid with metal carbonate or metal hydrogen carbonate:
When acids react with metal carbonate or metal hydrogen carbonate, most acids produce salt, water and carbon dioxide gas.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 6

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 13.
What happens when carbon dioxide in less proportion and excess proportion is passed through the solution of lime water? OR State the reactions that take place when carbon dioxide is passed through lime water (calcium hydroxide solution).
Answer:
On passing carbon dioxide in less proportion through lime water (calcium hydroxide solution), the solution turns milky because a white milky precipitate of calcium carbonate is formed.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 7
On passing excess carbon dioxide through lime water, precipitate of calcium carbonate dissolves due to formation of soluble calcium bicarbonate.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 8

Question 14.
What happens when an acid and a base react? Give one example.
Answer:
Reaction of acid with base:

  • When acid reacts with base, salt and water are produced.
  • Since base neutralizes the effect of acid, this reaction is called neutralization reaction.
    Acid → Base → Salt + Water

Example:
When sodium hydroxide, a base reacts with hydrochloric acid, it produces salt and water.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 9

Question 15.
What is formed when copper oxide reacts with dilute hydrochloric acid? State the change in colour that you will observe along with the balanced chemical reaction. OR What happens when a metal oxide reacts with acid? Give one example.
Answer:
Reaction of acid with metal oxide:
1. When acid reacts with metal oxide, salt and water are produced.
Acid + Metal oxide → Salt + Water

2. When hydrochloric acid reacts with copper oxide, a salt of copper (Il) chloride is formed.
Example:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 10
The colour of the solution is bluish-green due to the formation of copper chloride.

Question 16.
What happens when a non-metallic oxide reacts with a base?
Answer:
When a non-metallic oxide reacts with base, the reaction gives out salt and water.
Example:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 11

Question 17.
How are hydrogen ions produced when an acid is dissolved in water? Explain with necessary chemical equations. Also mention method of writing the hydrogen ions so formed.
Answer:
1. When an acid (or an acidic substance) dissolves in water, it produces hydrogen (H+) ions.
2. This happens because all acids contain positively charged hydrogen (H+) ions.
Example:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 12
Thus, hydrogen ion must always be written as H+(aq) or hydronium ion (H3O+).

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 18.
Write a brief note on base and alkali.
Answer:
Base:

  • Chemical or substances which are hydroxides of metal and have a bitter taste are called bases.
  • All metal oxides and metal hydroxide are bases.
  • Fo example, sodium hydroxide (NaOH), calcium oxide (CaO), calcium hydroxide Ca(OH)2, etc. are bases.
  • Washing soda (Na2CO3 10H3O), baking soda(NaHCO3), etc. are also bases or basic substances.

Alkali:

  • Those bases which can dissolve in water are called alkalis.
  • Sodium hydroxide (NaOH). potassium hydroxide (KOH), etc. are alkalis or say water soluble bases.
  • When a base (or a basic substance) is dissolved in water, it always produces hydroxide (OH) ions.
  • Thus base is a substance which dissolves in water to produce hydroxide (OH) ions in solution.

Example:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 14

As shown in the above reaction, when sodium hydroxide which is a base, is dissolved in water it produces hydroxide (OH) ions over and above sodium (Na+) ions.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 15

Here, when potassium hydroxide is dissolved in water, it gives hydroxide (OH) ions and potassium ions.

Question 19.
State the ions responsible for acidic and basic behaviour. Explain the acidic and basic behaviour by reaction with water.
Answer:
H+ or H3O+ ions in aqueous solution are responsible for acidic character and OH ions in an aqueous solution are responsible for basic character.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 16

H+(aq) ions are formed in aqueous solution of HCl. So it can be said that HCl is an acid.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 17

OH ions are formed in an aqueous solution of NaOH. So NaOH is a base.

Question 20.
One should dissolve acid in water cautiously. Give reason. OR During dilution, acid must be added to water, not vice-versa.
Answer:
1. The process of dissolving an acid or a base is highly exothermic.
2. If one adds acid to water suddenly and in large amount or if one adds water to acid, the reaction will emit a lot of heat. This can even break the glass container.
3. The hot contents may come out of the container with an explosion and burn our eyes and body.
4. Hence, while making dilute solution of acid, acid must only be added to water that too slowly and by stirring continuously.

Question 21.
What Is dilution? How do you prepare a dilute acid?
Answer:
1. The process of mixing an acid or base with water decreases the concentration of ions (H3O/OH) per unit volume. The acid/base so formed is called dilute acid/base.
2. For making dilute acid one should slowly add concentrated acid in small amounts to water and stir continuously.

Question 22.
Write a short note on strong and weak acids.
Answer:
Strong acids:
1. An acid which gets completely ionized completely in water or say which completely dissociates in water and produce a large amount of hydrogen [H+] ions (or say hydronium [H3O+] ions) is called a strong acid.
2. Depending upon their structures, different acids produce different number of H+ ions. For example, 1 mole of hydrochloric acid will produce more hydrogen [H+] ions as compared to 1 mole acetic acid.

Weak acids:
1. An acid which does not ionize completely (i.e. does not dissociate completely in water) and thus produce a small amount of hydrogen [H+] ions (or say H3O+ ions) is called a weak acid.
2. For example, when acids such as acetic acid, lactic acid, citric acid, tartaric acid, etc. are dissolved in water, they do not completely ionize and so are called weak acids.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 23.
Write a short note on strong and weak bases.
Answer:
Strong base:

  • A base, which completely ionizes in water and thus produces a large amount of hydroxide (OH) ions, is called a strong base or a strong alkali.
  • For example, when sodium hydroxide (NaOH) and potassium hydroxide (KQH) are dissolved in water, they completely get ionized and so are called strong bases.

Weak base:

  • A base, which does not ionize completely in water and thus produces a small amount of hydroxide (OH) ions, is called a weak base or a weak alkali.
  • For example, ammonium hydroxide (NH4OH) and calcium hydroxide Ca(OH)2 when dissolved in water do not completely ionize in water and so are considered weak bases.

Question 24.
Explain the methods of measuring the strength of an acid or a base. Strength (or weakness) of an acid or a base can be measured through following methods:
Answer:
(a) Through universal indicator :
1. Universal indicator is a mixture of many different indicators or say dyes which when added to a solution, changes the colour of the solution and thus indicate its pH value.

(b) Through pH scale:
1. To measure the acidic/basic nature of an aqueous solution, a scale called pH scale has been developed.
2. The pH scale measures concentration of hydrogen [H+] ions in the solution.
3. In German language, P of pH stands for ‘potenz’ i.e. power.
4. The scale points range from O to 14. 0 means very acidic and 14 means very alkaline. Scale point means neutral solution.
5. A lower pH value means there is higher concentration of H+ ions and hence the solution is acidic. So, as one moves towards O from 7, the solution goes on becoming more and more acidic.
6. Similarly, a higher pH value means there is lower concentration of H+ (and higher concentration of OH) ions and hence the solution is basic. So, as one moves from 7 to 14, the basicity of the solution increases.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 25.
Write a note on pH scale.
Answer:
Through pH scale:
1. To measure the acidic/basic nature of an aqueous solution, a scale called pH scale has been developed.
2. The pH scale measures concentration of hydrogen [H+] ions in the solution.
3. In German language, P of pH stands for ‘potenz’ i.e. power.
4. The scale points range from O to 14. 0 means very acidic and 14 means very alkaline. Scale point means neutral solution.
5. A lower pH value means there is higher concentration of H+ ions and hence the solution is acidic. So, as one moves towards O from 7, the solution goes on becoming more and more acidic.
6. Similarly, a higher pH value means there is lower concentration of H+ (and higher concentration of OH) ions and hence the solution is basic. So, as one moves from 7 to 14, the basicity of the solution increases.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 18

Question 26.
How do you measure the strength of an acid or a base?
Answer:
1. The strength of an acid is determined by the number of H ions it produces, where as strength of a base is determined by the number of OH ions the base produces.

2. If we take 1 molar concentration (1 mole or 1 m acid dissolved in 1 litre of solution) of hydrochloric acid and acetic acid, then the acid which produces more number of H+ ions will be considered the stronger among the two. In this case, hydrochloric is a strong acid whereas acetic acid is weak.

3. Using the same method one can find the strength or weakness of a base. However, in base, the OH ions are released and hence they are counted (instead of H+).

Question 27.
Discuss the importance of pH In daily life.
Answer:
Importance of pH In everyday life:
(1) Importance of pH in existence of living beings:

  • The physiological reactions occurring in our body takes place between a narrow range of 7.0 to 7.8 pH. If due to any reason the pH range gets disturbed, we may face several problems in the body.
  • Even other living beings cannot tolerate more changes in their pH level.
  • For example, when acid rain (i.e. rain having pH level of 5.6) falls into water reservoirs like rivers, ponds, etc., it decreases pH level of these water bodies and makes them highly acidic.
  • Under such circumstances, existences of aquatic organisms like fish, microorganisms and vegetation is risked.

(2) Importance of pH in soil:

  • Shrubs grow well if the pH level of soil is maintained between 6.5 to 7.3.
  • The soil having pH <6.5 is called acidic soil, and that having pH > 7.3 is called alkaline.

(3) Importance of pH indigestion of food:

  • Stomach plays an important role in digesting food.
  • When we eat food, stomach secretes hydrochloric acid, The pH of this acid ¡s between 1 and 3.
  • At such a low value of pH, an enzyme called pepsin becomes active which helps in digesting food.

(4) Importance of pH in stopping tooth decay:

  • The outer layer of the teeth is made up of calcium phosphate. This layer does not dissolve in water but gets decayed when pH of inner side of mouth becomes less than 5.5. This causes tooth decay.
  • When we eat food, bacteria decomposes the food particles that remain in the mouth and produce acid. This decreases the pH in the mouth.

(5) Self-defence by animals and plats through chemical warfare:

  • When a honey bee bites a human being, pain, irritation and swelling is felt at the site of bite.
  • This occurs because the honey bee releases acidic poison into human body during the bite.
  • To neutralize the effect of this acid to some extent, substances like baking soda are applied around the bite. Stinging hair of nestle leaves injects methanoic acid and causes burning pain.

Question 28.
Indigestion causes pain and irritation. Suggest how to cure this. OR How does baking soda help in relieving stomach pain and Irritation?
Answer:
1. During indigestion, the stomach produces excessive acid. This causes pain and irritation.
2. To neutralize the effect of the acid, bases must be used. Such bases are called antacids i.e. anti-acids.
3. Magnesium hydroxide (Milk of magnesia) is one such antacid. Baking soda is also a mild base which helps in neutralizing excess acid. (Note: Eno available in medical store is also one type of antacid.)

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 29.
When tooth pH goes below 5.5 it leads to decay. How would you prevent it?
Answer:
1. When pH in the mouth goes below 5.5, the bacteria of the mouth start producing acids and decaying the teeth.
2. The best way to prevent this is to clean the mouth properly after eating.
3. Toothpastes are basic in nature. Hence, cleaning the teeth with tooth paste neutralizes excess acid and prevents tooth decay.

Question 30.
What is acid rain? How does it affect aquatic life?
Answer:
1. If the pH of rain water becomes less than 5.6, then such rain is called acid rain.
2. When such acid water flows in water bodies such as rivers, ponds and lakes, it increases the acidity of these water sources.
3. The living organisms including humans have quite a narrow pH band of 7.0 to 7.8. Hence, even slightest change in water source makes survival difficult.

Question 31.
Why distilled (pure) water is used as a solvent in laboratories ? How does distilled water self – ionise?
Answer:
1. Distilled (pure) water is neutral. So in laboratories a solution is made using distilled water in order to get a correct pH value.
2. When an acid or a base is added to distilled water, the solution produces hydronium (H3O+) and hydroxide (OH) ions respectively through self ionization of water. The self-ionization reaction is as under:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 19

Question 32.
The aqueous solution of the salt produced by neutralization of weak acid and strong base possesses basic nature, while aqueous solution of salt produced by neutralization reaction of weak base and strong acid possess acidic nature – Explain.
Answer:
1. When the pH level of an aqueous solution increases more than 7, the solution goes on becoming basic.
2. In a neutralization reaction, when a weak acid and a strong base react, the salts obtained in the reaction hydrolyse to produce hydroxide [OH] ions.
3. As the level of [OH] ions increases in the solution, the solution becomes basic in nature.
4. In case, when in neutralization reaction, reaction takes place between a weak base and a strong acid, the salt obtained in the reaction hydrolyses in water to produce hydronium [H3O+] ions.
5. The increased level of [H3O+] ions in the aqueous solution makes the solution acidic.
6. Thus, the aqueous solution of the salt produced by neutralization reaction of weak acid and strong base possesses basic nature, while aqueous solution of salt produced by neutralization reaction of weak base and strong acid possess acidic nature.

Question 33.
What is neutralization reaction?
Answer:
Neutralization reaction:
1. When an acid and a base are mixed in right proportion, both acid and base lose their properties. Such a reaction is called neutralization reaction.

2. Thus, the reaction of acid and base is called a neutralization reaction. Moreover, reaction of acid and base gives us ‘salt’ and ‘water’.

Neutralization reaction can be generalized as follows:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 20
Where, H refers to hydrogen ion
OH refers to hydroxide ion
MX refers to Salt
HOH refers to water (H2O)
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 21

Question 34.
What s a salt?
Answer:
1. A salt is an ionic compound which is formed by the neutralization reaction of an acid and a base. Thus, we get salt when we react an acid with a base.
2. When we dissolve a salt in water it will get ionized and release cation (i.e. the positive +ve ion) and anion (i.e. the negative -ve ion).
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 22

3. ‘Salt’ is a general name and it does not refer only to NaCl i.e. sodium chloride. There exists a huge number of salts other than NaCl.
4. NaCl i.e. common salt so formed can be further used to produce several other products.
5. Sodium hydroxide (NaOH), baking soda (NaHCO3), washing soda (Na2CO3 10H2O), bleaching powder (CaOCl2) are all examples of salts.

Question 35.
How does a salt gets its name?
Answer:
The general form of naming a salt is ‘cation anion’. This means the name of cation (i.e. the positive +ve ion) of the salt will be put first and then name of its anion (i.e. the negative -ve ion) will be put second.
Example:
(a) NaCl: In NaCl salt, sodium Na+ has positive ions i.e. cations and chlorine CF has negative ions i.e. anions. Hence, we call NaCl salt as sodium chloride.

(b) K2SO4: Applying the same rule, the name of this salt is potassium sulphate.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 36.
What is a family of salts?
Answer:
1. There are several types of salts. The properties of all the salts are not completely different. In other words, properties of several salts are similar.
2. In general, salts having same type of cations (+ve ions) or anions (-ve) belong to the same family.
Example:
(a) Family of sodium salts (salts having Na ion): Na2SO4, NaCl, NaNO3, Na2CO3
(b) Family of chloride salts (salts having C ion): NaCl NH4Cl
(c) Family of sulphate salts (salts having SO4 ion): K2SO4, Na2SO4, Ca2SO4, MgSO4, CuSO4

Preparation of Important Salts
List of important salts that we will study in this section.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 23

Question 37.
What is brine? State its two important uses.
Answer:
1. The concentrated solution of sodium chloride i.e. concentrated solution of NaCl + H2O is called brine.
2. Brine is used for preparing many compounds, however two products are prepared directly using brine.
They are:

  • Caustic soda (sodium hydroxide) and
  • Baking soda (sodium hydrogen carbonate).

Question 38.
Write a note on causltc soda (sodium hydroxide). OR Write a note on chlor-alkali process. Chemical name of caustic soda: Sodium hydroxide
Answer:
Chemical formula: NaOH
Preparation:
1. When electricity is passed through brine, it gets decomposed and produces three products. They are:

  • Sodium hydroxide,
  • Chlorine gas and
  • Hydrogen gas.

Reaction:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 24

2. The chlorine gas is produced at anode (+ve electrode) and hydrogen at cathode. Sodium hydroxide is formed near the cathode.

3. The process of preparing NaOH is also called chlor-alkali process because the process gives out sodium hydroxide which is an alkali and chlorine.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 39.
State uses of the products formed in the chior-alkali process.
Answer:
Uses of products formed in chlor-aikali process:

  • NaOH: Making soap and detergent, paper, artificial fibres, de-greasing metals, etc.
  • Chlorine gas: To disinfect water, added in swimming pools, making PVC, CFCs and pesticides
  • Hydrogen gas: As a fuel, for making fertilizers and in making margarine

Question 40.
Write a note on preparation of baking soda.
Answer:
Chemical name of baking soda: Sodium hydrogen carbonate
Chemical formula: NaHCO3

Preparation:
When brine reacts with ammonia in the presence of carbon dioxide gas, it produces sodium hydrogen carbonate and ammonium chloride.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 24

Baking soda is a mild, non-corrosive basic salt.

Question 41.
Give an idea and preparation about soda ash. OR What happens when you heat baking soda? OR State and explain the reaction of baking soda when it Is heated during cooking. OR State the preparation of sodium carbonate.
Answer:
Chemical name of soda ash: Sodium carbonate
Chemical formula: Na2CO3
Preparation:
When baking soda gets heated during cooking, it produces sodium carbonate (soda ash) along with carbon dioxide and water.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 26

Question 42.
What happens when baking soda is heated or mixed with water? When baking soda is heated or mixed with water than following action takes place:
Answer:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 27
Carbon dioxide produced during this reaction causes bread or cake to rise making them soft and spongy.

Question 43.
Mention uses of baking soda:
Answer:
1. Baking socia is a soda (or a salt) commonly used in kitchen for making cakes, crispy pakoras, khaman, etc.
2. It is used for making baking powder commonly used in kitchen.
3. It is also used in making antacids. Antacids cure acidity of stomach.
4. To make soda-acid fire extinguishers
5. To make several industrial products

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 44.
How is washing soda prepared?
Answer:
Chemical name of washing soda: Sodium carbonate decahydrate
Chemical formula: Na2CO3 10H2O
Preparation:
When sodium carbonate (i.e. soda ash) is dissolved in water, and recrystallized it gives washing soda crystals containing 10 molecules of water of crystallization.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 28
Washing soda is a basic salt.

Question 45.
What does the number 10 represents In the formula Na2CO3 10H2O i.e. the formula of washing soda?
Answer:
The number 10 in the formula Na2CO3 10H2O tells us that there are lo water molecules in washing soda. Hence, it is also called decahydrate.

Question 46.
State the uses of washing soda.
Answer:
Uses of washing soda:

  • It is used in making glass and paper.
  • It is used for making sodium based compounds such as borax.
  • It is used as a cleaning agent such as washing powder and soap.
  • For removing permanent hardness of water.

Question 47.
Write a note on preparation of bleaching powder and its uses.
Answer:
Chemical name of bleaching powder: Calcium oxy-chloride
Chemical formula: CaOCl2
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 29
Preparation:
1. It is prepared by the action of chlorine on slaked lime (Calcium hydroxide).
2. On passing chlorine gas over dry slaked lime (CaCOH2), bleaching powder is obtained.

Uses of bleaching powder:

  • For bleaching cotton and linen clothes in textile industry, for bleaching wood pulp in paper-making factories and bleaching washed clothes in laundries.
  • As an oxidizing agent in many chemical industries.
  • For disinfecting drinking water to make it free of germs.

Question 48.
State the uses of bleaching powder.
Answer:
Uses of bleaching powder:

  • For bleaching cotton and linen clothes in textile industry, for bleaching wood pulp in paper-making factories and bleaching washed clothes in laundries.
  • As an oxidizing agent in many chemical industries.
  • For disinfecting drinking water to make it free of germs.

Question 49.
What is plaster of Paris? State its chemical name and preparation.
Answer:
Chemical name of plaster of Paris (POP): Calcium sulphate hemihydrate (hemi = half or say 1/2)
Chemical formula: CaSO4 \(\frac{1}{2}\)H2O (OR 2CaSO4 . H2O)

Preparation:
CaSO 2H2O refers to a compound called gypsum. Its chemical name is calcium sulphate dehydrate (de =2).
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 30

  • On heating gypsum at 373 K, it loses water molecules and forms calcium sulphate hemihydrate (Plaster of Paris) and \(1 \frac{1}{2}\) molecule of water.
  • In CaSO4 . \(\frac{1}{2}\)H2O, the half molecule of water is attached as water of crystallization.
  • Plaster of Paris is a white powder. On adding water, it again turns to gypsum having hard solid mass.

Question 50.
What do doctors use to join the fractured bones?
Answer:
1. Doctors use white powder of plaster of Paris to join the fractured bones.
2. On adding water to this powder, it forms a paste which can be easily applied on the fractured area. When the paste becomes dry it becomes solid hard substance called gypsum.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 31

Question 51.
What is water of crystallization? Give examples.
Answer:
(a) The fix number of water molecules present in one formula unit of salt is called water of crystallization.
Examples:
(1) Calcium suphate hemihydrate (CaSO4. H2O) contains 1/2 i.e. half molecule of water of crystallization.
(2) Sodium carbonate decahydrate (Na2CO3 . 10H2O) contains 10 molecules of water of crystallization.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 52.
List out two differences between acids and base on the basis of their chemical properties.
Answer:

AcidBase
1. When acids are dissolved in water they release (H+) ions.
2. Acid reacts with lime stone to liberate carbon dioxide gas.
1. When bases are dissolved in water they release (OH) ions.
2. Base reacts with oils to form soapy solution.

Question 53.
State two difference between organic acid and mineral acid.
Answer:

Organic acid

Mineral acid

1. Acids present in plants and animais i.e. occurring naturally are called organic acids.
Example: Citric acid, lactic acid, etc. are organic acids.
1. Acids prepared from minerals found in earth are called mineral acids.
Example: Hydrochloric acid, sulphuric acid, etc. are mineral acids.

Question 54.
What will be the action of the following substances on litmus paper? Dry HCl gas, Moistened NH3 gas, Lemon juice, Carbonated soft drink, Curd, Soap solution.
Answer:
1. Dry HCl gas: No change on litmus paper
2. Moistened NH3 gas: Red litmus will turn blue.
3. Lemon juice: Blue litmus will turn red.
4. Carbonated soft drinks: They contain carbonic acid. So blue litmus will turn red.
5. Curd: It contains lactic acid. So, blue litmus will turn red.
6. Soap solution: It is basic. So, red litmus will turn blue.

Question 55.
Name the acid present in ant sting and give its chemical formula. Also give the common method to get relief from the discomfort caused by the ant sting.
Answer:
When ant stings, it releases formic acid (or methanoic acid) in our body. Its chemical formula is HCOOH. Mix some baking soda with water and apply it on the sting. Baking soda is basic and so it will neutralize the acidic effect and provide relief.

Question 56.
What happens when nitric acid is added to egg shell?
Answer:
Egg shells contain calcium carbonate (CaCO3). When nitric acid (HNO3) is added to it, it results in brisk effervescence due to the formation of CO2 gas. The reaction is as follows.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 33

Question 57.
A student prepared solutions of (i) an acid and (ii) a base in two separate beakers. She forgot to label the solutions and litmus paper is not available In the laboratory. Since both the solutions are colourless, how will she distinguish between the two?
Answer:
Since the student does not have litmus, she can use any other indicator like methyl orange, phenolphthalein, etc. She can also use a natural indicator such as turmeric.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 58.
When zinc metal is treated with a dilute solution of a strong acid, a gas s evolved, which is utilized in the hydrogenation of oil. Name the gas evolved. Write the chemical equation of the reaction involved and also write a test to detect the gas formed.
Answer:
When zinc reacts with dilute solution of strong acid (like hydrochloric acid HCl), it forms salt and hydrogen gas is evolved which is used in hydrogenation of oil.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 41
To test the presence of H2 gas take a burning candle near the mouth of the test tube. The gas burns with a pop sound indicating presence of hydrogen gas.

Question 59.
How would you distinguish between baking powder and washing soda by heating?
Answer:
On heating baking soda (NaHCO3), carbon dioxide (CO2) gas is produced. It turns lime water milky.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 42

If you heat washing soda (Na2CO3 . 10H2O), water of crystallization is given out and the sail becomes anhydrous. The presence of water of crystallization given as product can be tested b treating it with anhydrous CuSO4. It is white coloured which turns blue when it comes in contact ol anhydrous CuSO4.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 43

Question 60.
Salt A commonly used in bakery products on heating gets converted Into another salt B Which itself Is used for removal of hardness of water and a gas C is evolved. The gas C when passed through lime water, turns It milky. Identify A, B and C.
Answer:
Salt A: It is used in bakery and also gives Na2CO3 . Hence it is sodium bicarbonate NaHCO3.
Salt B: It is sodium carbonate Na2CO3 because it is used for removal of hardness of water.
Gas C: It turns lime water milky and hence gas C is carbon dioxide CO2.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 44

Question 61.
A compound X of sodium is commonly used In kitchen for making crispy pakoras. It is also used for curing acidity in the stomach. Identify X. What is its chemical formula? State the reaction which takes place when it is heated during cooking.
Answer:
Compound X: Sodium bicarbonate or sodium hydrogen carbonate or baking soda
Formula: NaHCO3
Chemical reaction:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 45

Question 62.
For making cake, baking powder is taken. If at home your mother uses baking soda instead of baking powder in cake,
(a) How will it affect the taste of the cake and why?
(b) How can baking soda be converted into baking powder?
(c) What is the role of tartaric acid added to baking soda?
Answer:
(a) Baking powder contains tartaric acid. This acid reacts with sodium carbonate (Na2CO3) produced during decomposition of NaHCO3 and neutralizes it.
If only sodium hydrogen carbonate (baking soda) is used in making cake, then sodium carbonate formed from it by the action of heat (during baking) will give a bitter taste to cake.
(b) By adding tartaric acid to baking soda we can convert baking soda into baking powder.
(c) Tartaric acid neutralizes the sodium carbonate formed during decomposition of NaHCO3. Hence, it makes the cake tasty and prevents it from becoming bitter in taste.

Question 63.
“The aqueous solution of the salt produced by neutralization of weak acid and strong base possesses basic nature, while aqueous solution of salt produced by neutralization of weak base and strong acid possesses acidic nature.” Explain.
Answer:
1.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 46
2. When we react carbonic acid which is a weak acid with a strong base of sodium hydroxide what we get is sodium carbonate.
3. The aqueous solution of sodium carbonate contains higher concentration of OH ions. Hence, the solution possesses basic nature.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 47

4. When we react hydrochloric acid which is a strong acid with a weak base, we get ammonium chloride.
5. This aqueous solution contains higher concentration of H+(aq) ions compared to the concentration of OH+ (aq) ions. Therefore solution possesses acidic nature.

Question 64.
Identify compound X on the basis of the reactions given below. Also, write the name and chemical formulae of A, B and C.
Answer:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 50

Question 65.
While eating food, you spill some curry on your white shirt. You immediately scrub It with soap.
What happens to its yellow colour on scrubbing with soap? Why? What happens to this stain. when the shirt is washed with plenty of water?
Answer:
When we scrub the shirt with soap, its colour changes from yellow to reddish brown. This happens because soap is basic in nature and the colour of turmeric changes from yellow to reddish brown in basic medium. If we wash the shirt with plenty of water, the stain will again turn yellow.

Very Short Answer Type Questions

Question 1.
How can we broadly classify all the compounds known to us?
Answer:
All the compounds that exist can be classified as

  • Acids,
  • Bases or
  • Salts.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 2.
What are acids? Name two acids.
Answer:
Substances which when dissolved in water release hydrogen ions (H+) are called acids. Hydrochloric acid and sulphuric acid are two common acids.

Question 3.
State two properties of acids.
Answer:
Acids are sour in taste, Acids conduct electricity when dissolved in water, Acids react with metals to form salt and hydrogen gas.

Question 4.
What are bases?
Answer:
Bases are hydroxides of metals which give hydroxide (OH) ions when mixed with water.

Question 5.
State two properties of bases.
Answer:
Bases have a bitter taste. They change red litmus paper to blue.

Question 6.
What is salt?
Answer:
A salt is an ionic compound which is formed from the neutralization reaction of an acid and a base. Thus, we get salt when we react an acid with a base.

Question 7.
Read the paragraph and point out the erroneous statement.
Answer:
Acids are sour and they release H+ ions. Bases are bitter and they released H3O+ ions. Also, bases turn litmus paper blue. Litmus is an artificial indicator to test presence of acids.

  • Bases are sour
  • Litmus is natural
  • Bases release H+ ions Statement (i) and (iii) are erroneous.

Question 8.
Name two natural and synthetic indicators.
Answer:
1. Natural: Litmus and turmeric,
2. Synthetic: Methyl orange and phenolphthalein.

Question 9.
A knife, which is used to cut a fruit, was immediately dipped into water containing drops of blue litmus solution. If the colour of the solution changes to red, what inference can be drawn about the fruit and why?
Answer:
Since the colour of blue litmus turned red, the fruit is acidic.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 10.
What is an olfactory indicator?
Answer:
A substance whose smell changes in acidic or basic solution is called an olfactory indicator.

Question 11.
Name two olfactory indicators.
Answer:
Onion and vanilla extract.

Question 12.
What is a concentrated acid?
Answer:
An acid that contains minimum amount of water is called a concentrated acid.

Question 13.
What is a dilute acid?
Answer:
An acid obtained by mixing concentrated acid with large amount of water is called a dilute acid.

Question 14.
Name a substance that does not contain hydroxide ion yet it acts as a base. Also give its formula.
Answer:
Ammonia (NH3)

Question 15.
You are given gold, silver and platinum. Which of these will not react with acid easily? Why?
Answer:
None. Because all are noble metals.

Question 16.
What will happen if you add zinc granules to dilute sulphuric acid?
Answer:
Bubbles containing H2 gas will be formed on zinc granules.

Question 17.
Rasika took some dilute sulphuric acid in a test tube and added a few pieces of zinc granules to it. Her friend Shyam was supposed to write the observation in the journal but he was absent that day. As a science student write the observation that must have taken place in this experiment.
Answer:
We can observe that bubbles form on the surface of zinc granules indicating formation of gas. When we pass this gas through the soap solution, the gas gets trapped in soap molecules and bubbles are formed. The gas is hydrogen and it burns with a pop sound when a burning candle is brought near it.

Question 18.
What will be produced when you pass carbon dioxide gas through lime water?
Answer:
A milky precipitate of calcium carbonate (CaCO3).

Question 19.
Take a small amount of copper oxide in a beaker and add dilute hydrochloric acid in it. State the chemical reaction.
Answer:
CuO + 2HCl CuCl2 + H2O

Question 20.
You might have seen lemon or tamarind juice being used to clean tarnished surface of copper vessels. Explain why these sour substances are effective in cleaning the vessels?
Answer:
Copper is metal whereas lemon juice and tamarind are acidic. When acid reacts with metal oxides, salt and water is formed. This makes the metal vessels shiny again

Question 21.
Why lemonade should not be prepared in copper vessel?
Answer:
Lemon is highly acidic and reacts vigorously with copper metal and causes copper poisoning. Hence………..

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 22.
Take about 0.5 g of sodium carbonate (Na2CO3) in test tube A and about 0.5 g of sodium hydrogencarbonate (NaHCO3) in test tube B. Add about 2 mL of dilute HCl in both the test tubes. State the observation of this experiment.
Answer:
When acids react with metal carbonates and metal hydrogen carbonates, they produce salt, water and carbon dioxide gas. This happens in both the test-tubes.

Question 23.
Look at the reaction given below and mention what will happen if you pass excess carbon dioxide from it. Also state the reaction.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 51
Answer:
On passing excess carbon dioxide through the given solution, precipitate of calcium carbonate dissolves due to formation of soluble calcium ‘ bicarbonate.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 52

Question 24.
What is neutralization reaction?
Answer:
When acid and base mix in right proportions, both of them lose their properties and produce salt and water. Such a reaction is called neutralization : reaction.

Question 25.
What will be the colour of solution if you add two drops of phenolphthalein solution in dilute NaOH solution?
Answer:
The solution will become pink.

Question 26.
Why does the colour of phenolphthalein
Answer:
NaOH gets neutralized by acid. Hence, the colour of phenolphthalein changes.

Question 27.
Give the neutralization reaction of potassium hydroxide with sulphuric acid.
Answer:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 53

Question 28.
Write one word for the following:
(a) Water soluble base
(b) A substance which dissociates on dissolving in water to produce hydroxide ions.
Answer:
(a) Alkali
(b) Base

Question 29.
Write one word for the following:
(a) A substance which dissociates on dissolving in water to produce hydrogen ions.
(b) A reaction between an acid and a base to form salt and water.
Answer:
(a) Acid,
(b) neutralization

Question 30.
Give reason in one sentence: ‘Solution of sulphuric acid conducts electricity whereas alcohol does not’.
Answer:
Solution of sulphuric acid contains charged ions H+ and SO4-2 which helps in conducting electricity whereas alcohol does not. Hence,………..

Question 31.
Although compounds like alcohol and glucose contain hydrogen, they are not acids. Why?
Answer:
Although alcohol and glucose contain hydrogen, they do not give hydrogen ions in water and hence are not categorized as acids.

Question 32.
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 54What is happening in this reaction?
Answer:
Here, when potassium hydroxide, a base is subjected to water, it generates hydroxide (OH) ions. Which out of the solutions of glucose,

Question 33.
Which out of the solutions of glucose, alcohol, hydrochloric acid, sulphuric acid and sodium hydroxide, will not conduct electricity?
Answer:
Glucose and alcohol will not conduct electricity because they will not release ions.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 34.
What will happen it you add water to strong acid for producing a dilute acid?
Answer:
A lot of heat will be produced. This may splash out the acid and burn our bodies. Even the glass container may break.

Question 35.
What is dilution?
Answer:
Mixing acid or base with water results in decrease in the concentration of H3O+ or OH ions per unit volume. Such a process ¡s called dilution and the acid/base is called diluted.

Question 36.
An experiment was done in which about 1g solid NaCl was taken in a clean and dry test tube. Then some concentrated sulphuric acid was added to the test tube. The reaction produced hydrochloric acid. On the basis of the above activity, what do you infer about the acidic character of : (i) Dry HCl gas, (ii) HCl solution?
Answer:
The experiment suggests that hydrochloric acid produces hydrogen ions in the presence of water. But, dry hydrochloric acid does not release hydrogen ions. Thus, only HCl solution is acidic whereas dry HCl is not.

Question 37.
What is a universal Indicator?
Answer:
An indicator which can pass through a series of colour changes over a wide range of H3O+ ion concentration is called universal indicator. It is a mixture of several indicators.

Question 38.
What is pH scale?
Answer:
A scale that measures the concentration of hydrogen ion in a solution is called a pH scale.

Question 39.
Arrange the following in an increasing order of their pH values: NaOH solution blood, lemon juice.
Answer:
NaOH < Blood < Lemon juice

Question 40.
Why 1M HCl solution will have a higher concentration of H ions compared to 1M CH3COOH solution?
Answer:
1. HCl i.e. hydrochloric acid is a strong acid. Hence, HCl molecules dissociate completely into H+ ions and Cl ions and produce more H+ ions.
2. CH3COOH i.e. acetic acid is a weak acid and so it does not dissociate completely. Hence, it produces less H+ ions. As a result

Question 41.
A student added a few drops of liquid P into distilled water. He observed that the pH of the water decreased. Can you guess the pH of the liquid P?
Answer:
We know that pH of distilled water is 7. On adding liquid P, the pH of the water decreased which means that P could be any acid such as HCl or H3SO4, etc.

Question 42.
Which type of substances are taken for getting relief from acidity?
Answer:
Basic substances or say antacids

Question 43.
Separate the following acids into strong acids and weak acids. Hydrochloric acid, citric acid, acetic acid, nitric acid, formic acid, sulphuric acid.
Answer:
Strong acid: Hydrochloric acid, nitric acid and sulphuric acid:
Weak acid: Citric acid acetic acid and formic acid

Question 44.
What do you mean by family of salts?
Answer:
1. There are several types of salts. The properties of all the salts are not completely different, In other words, properties of several salts are similar.
2. In general, salts having same type of cations (+ve ions) or anions (-ve) belong to the same family.

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 45.
Which salt do you obtain by the reaction of hydrochloric acid and sodium hydroxide?
Answer:
Sodium chloride (NaCl)

Question 46.
Name two salts that you can directly prepare from brine.
Answer:
(1) Caustic soda (sodium hydroxide) and
(2) Baking soda (sodium hydrogen carbonate).

Question 47.
State chemical reaction for preparing caustic soda.
Answer:
Reaction:
HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts 55

Question 48.
What is chlor-alkali process?
Answer:
When electricity is passed through an aqueous solution of sodium chloride, it decomposes to form sodium hydroxide and chlorine gas. This process is called chlor-alkali process.

Question 49.
How does the soda-acid fire-extinguisher extinguish the fire?
Answer:
Soda-acid fir-extinguisher extinguishes the fire by stopping the contact of air with fire.

Question 50.
How is bleaching powder produced? State is reaction.
Answer:
Bleaching powder is produced by the action of chlorine on dry slaked lime (Calcium hydroxide)
Ca(OH)2 + Cl2 → CaOCl + H2O

Question 51.
State two uses of bleaching powder.
Answer:
(a) For bleaching cotton and linen in textile industry.
(b) For disinfecting drinking water.

Question 52.
What is baking powder?
Answer:
Baking powder is a mixture of baking soda and a mild edible acid such as tartaric acid.

Question 53.
Why baking soda is used in making antacid?
Answer:
Baking soda is alkaline and so it neutralizes excess acid in the stomach and provides relief from acidity. Hence, it is …………..

Question 54.
Recrystallization of sodium carbonate gives washing soda. State the reaction.
Answer:
Na2CO3 + 10H2O → Na2CO3 10H2O

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

Question 55.
State two uses of washing soda.
Answer:
(a) To prepare glass and soap,
(b) To remove permanent hardness of water

Question 56.
State two uses of POP.
Answer:
(a) Doctors use POP for setting fractured bones.
(b) It is used for making false and decorative ceilings.

Fill in the Blanks:

1. When NaOH is added to a cloth strip treated with onion extracts, the onion smell ……………………..
Answer:
Cannot be detected OR Vanishes.

2. Cloth strip treated with onion + dilute. NaOH solution = …………………… (state observation)
Answer:
Onion smell will not be detected in the cloth and the cloth will change to green colour.

3. H+ ions cannot separate from HCl molecules in the absence of …………..
Answer:
Water

4. For a neutralization reaction, H X + M OH → ………………..
Answer:
MX + HOH

5. Universal indicator is used for …………………
Answer:
Obtaining approximate pH of a solution.

6. In pH scale, scale points O’ = and
Answer:
O = very acidic, 14 = very basic

7. Generally, with the universal indicator is used to measure pH.
Answer:
Paper impregnated

8. Higher the hydronium ion concentration, is the pH value.
Answer:
Lower

9. If OH> 10-7, solution will be
Answer:
Basic

10. If a red litmus paper is dipped into a solution and it turns blue, then it can be said that the solution has pH range between
Answer:
7and 14

11. In order to have good growth and development of shrubs, the soil should have pH
Answer:
Near 7

12. Bacteria present in the mouth produce base by degradation of food particles left in the mouth after eating.
Answer:
False

13. Two substances that have almost equal neutral pH are ………………..
Answer:
Blood and water

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

14. The pH values of aqueous solutions A, B, C and D are 2.9, 3.5, 1.6 and 4.2 respectively. The correct order of their acidic strength is …………………….
Answer:
C>A> B>D

15. …………….. decreases the pH inside the mouth.
Answer:
Acids

16. Aqueous solution of is applied around the place of bite, to get relief from the effect of bite of honey bee.
Answer:
Baking soda

17. The sting of nettle leaves inject (name of the compound) in the body.
Answer:
4 Methanoic acid

18. The other name and formula of calcium sulphate hemihydrate …………..
Answer:
Plaster of Paris : CaSO4 \(\frac{1}{2}\)H2O.

True Or False

1. The solution which has no effect on any litmus paper is neutral. — True
2. Tartaric acid is stronger than nitric acid. — False
3. As a thumb rule, all organic acids are weak acids and mineral acids are strong acids. — True
4. H3O+ = OH = 10-7 — True
5. Sodium hydroxide and magnesium hydroxide are basic and hence work quite well in curing stomach acidity. — False
6. Hydrogen ions cannot exist alone. — True
7. HCl solution is acidic but its dry form is not. — True
8. Dissolution of acid (or base) in water releases is an endothermic process. — False
9. Limestone, marble and chalk are forms of calcium carbonate. — True
10. The pH of a neutral solution is O. — False
11. The pH of gastric juices is about 1.2. — False
12. You need to heat gypsum at 378 K for forming calcium sulphate hemihydrate. — False
13. Carbon dioxide gas is mainly responsible for making the cake soft. — True
14. If we make the crystals moist, we can see blue colour of copper sulphate reappearing. — True

Match the Following

1. Match the acids given in Column (A) with their correct source given in Column (B)

Column (A)

Column (B)
(a) Lactic acid
(b) Acetic acid
(c) Citric acid
(d) Oxalic acid

(i) Tomato
(ii) Lemon
(iii) Vinegar
(iv) Curd

Answer:
(a-4) (b-3) (c-2) (d-1)

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts

2. Match the important chemicals given in Column (A) with the chemical formulae given in Column (B)

Column (A)Column (B)
(a) Plaster of Paris
(b) Gypsum
(C) Bleaching Powder
(d) Slaked Lime
(i) Ca(OH)2
(ii) CaSO4
(iii) CaSO4 1/2 H2O
(iv) CaOCl2 . 2H2O

Answer:
(a-2) (b-3) (c-4) (d-1)

 

HBSE 10th Class Science Important Questions Chapter 2 Acids, Bases and Salts Read More »

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Haryana State Board HBSE 10th Class Maths Important Questions Chapter 6 Triangles Important Questions and Answers.

Haryana Board 10th Class Maths Important Questions Chapter 6 Triangles

Short/Long Answer Type Questions

Question 1.
In the adjoining figure, DE || BC, find the length of side AD, given that AE = 1.8 cm, BD = 7.2 cm and CE = 5.4 cm.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 1
Solution :
We have
AE = 1.8 cm, BD = 7.2 cm, CE = 5.4 cm and DE || BC
∴ \(\frac{\mathrm{AD}}{\mathrm{BD}}=\frac{\mathrm{AE}}{\mathrm{CE}}\)
[By theorem 6.1 (BPT)]
⇒ \(\frac{\mathrm{AD}}{\mathrm{7.2}}=\frac{\mathrm{1.8}}{\mathrm{5.4}}\)
⇒ AD = \(\frac{7.2 \times 1.8}{5.4}\)
⇒ AD = \(\frac{7.2 \times 1.8}{54}\) = 2.4 cm

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 2.
In the given fig. ∠D = ∠E and \(\frac{\mathrm{AD}}{\mathrm{DB}}=\frac{\mathrm{AE}}{\mathrm{EC}}\) prove that ΔBAC is an isosceles triangle.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 2
Solution :
We have, In triangle ABC,
\(\frac{\mathrm{AD}}{\mathrm{DB}}=\frac{\mathrm{AE}}{\mathrm{EC}}\)
⇒ DE || BC (By converse of BPT)
DE || BC and AD is a transversal line
∠D = ∠B (Corresponding angles) … (1)
DE || BC and AC is a transversal line, So, ∠E = ∠C (Corresponding angles) …(2)
But ∠D = ∠E ……(3)
From equ. (1), (2) and (3) we get
∠B = ∠C
⇒ AB = AC [Sides opp. to equal angles are equal]
Hence Proved.

Question 3.
In the adjoining figure, DE || AC and DC || AP. Prove that \(\frac{\mathrm{BE}}{\mathrm{EC}}=\frac{\mathrm{BC}}{\mathrm{CP}}\)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 3
Solution :
In ΔABP, we have DC || AP
∴ \(\frac{\mathrm{AD}}{\mathrm{BD}}=\frac{\mathrm{BC}}{\mathrm{CP}}\) …….(1)
[By BPT]
Again, In ΔABC, we have
DE || AC
∴ \(\frac{\mathrm{AD}}{\mathrm{BD}}=\frac{\mathrm{BE}}{\mathrm{EC}}\) ……….(2)
From equation (1) and (2), we get
∴ \(\frac{\mathrm{AD}}{\mathrm{BD}}=\frac{\mathrm{BE}}{\mathrm{EC}}\)
Hence Proved.

Question 4.
In the adjoining figure, if ΔABC ~ ΔDEF and their sides of length (in cm) are marked along them, then find the lengths of the sides of each triangle.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 4
Solution :
We have, ΔABC ~ ΔDEF
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 5
⇒ 2x – 1 = \(\frac {18}{2}\) and 4x + 4 = 3x + 9
⇒ 2x = 9 + 1 and 4x – 3x = 9 – 4
⇒ 2x = 10 and x = 5
⇒ x = 5 and x = 5
Substituting the value of x in the length of sides of two triangles, we get
AB = 2x – 1 = 5 × 2 – 1 = 9 cm
BC = 2x + 2 = 5 × 2 + 2 = 12 cm
AC = 3x = 5 × 3 = 15 cm
DE = 18, EF = 3x + 9
= 3 × 5 + 9 = 24 cm
And DF = 6 × x = 6 × 5 = 30 cm
Hence, sides of ΔABC are 9cm, 12 cm, 15 cm, and sides of ΔDEF are 18 cm, 24 cm and 30 cm.

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 5.
In similar triangle ABC and PQR, AD and PM are the medians respectvely, prove that \(\frac{\mathrm{AD}}{\mathrm{PM}}=\frac{\mathrm{AB}}{\mathrm{PQ}}\)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 6
Solution :
Given : AD and PM are medians of ΔABC and ΔPQR and ΔABC ~ ΔPQR.
To prove : \(\frac{\mathrm{AD}}{\mathrm{PM}}=\frac{\mathrm{AB}}{\mathrm{PQ}}\)
Proof : ΔABC ~ ΔPQR
∴ ∠B = ∠Q
(Corresponding ∠S of similar triangles)….(1)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 7
and ∠B = ∠Q [proved above] …………..(1)
From (1), ∠2, ΔABC ~ ΔPQM [By SAS similarity criterian]
⇒ \(\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{\mathrm{AD}}{\mathrm{QM}}\)
[Corrosponding sides of similar triangles]

Question 6.
X is a point on side BC of ΔABC, XM and XN are drawn parallel to AB and AC respectively meeting AB in N and AC in M. MN produced meets CB produced at T. Prove that TX2 = TB × TC
Solution :
In ΔTCM, XN||CM
∴ ΔTXN ~ ΔTCM
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 8
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 9

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 7.
Given ΔABC ~ ΔPQR, if \(\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{\mathrm{1}}{\mathrm{3}}\) then \(\frac{a r(\triangle \mathrm{ABC})}{a r(\Delta \mathrm{PQR})}\) = …………..
Solution :
Since ΔABC ~ ΔPQR
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 25

Question 8.
ΔABC and ΔBDE are two equilateral triangle such that D is the mid point of BC. Ratio of the areas of triangles ABC and BDE is …………………
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 10
Solution :
Let each side of equilateral ABC be 2x units then BD = \(\frac {2x}{2}\) [D is the mid point of BC]
⇒ BD = x units
Each of anlge ΔABC is 60° (equilateral Δ)
Each angle of ΔBDE is 60° (equilateral Δ)
ΔABC ~ ΔBDE (By AAA similarity criterian)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 26

Question 9.
The area of two similar triangles are in the ratio 16 : 18. Find the ratio of its sides.
Solution :
Let ΔABC ~ ΔPQR
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 11

Question 10.
If the ratio of corresponding medians of two similar triangles are 9 : 16, then find the ratio of their area.
Solution :
We have,
Ratio of corresponding medians of two similar triangles = 9 : 16
We know that, Ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medi
= 81 : 256

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 11.
If ΔABC – ΔDEF in which AB = 1.6 cm and DE = 2.4 cm. Find the ratio of areas of ΔABC and ΔDEF.
Solution :
∵ ΔABC ~ ΔDEF
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 12

Question 12.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 27
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 13
Solution :
We have, In ΔABC, MN || BC
∴ ΔAMN ~ ΔABC
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 14
Substituting the value of \(\frac {AM}{AB}\) in the equation (1), we get
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 28

Question 13.
In the given figure, ∠ACB = 90° and CD ⊥ AB. Prove that CD2 = BD × AD.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 15
Solution :
Given : A ΔABC i. which ∠ACB = 90° and CD ⊥ AB
To prove : CD2 = BD × AD
Proof: In Right ΔADC,
∠1 + ∠2 + ∠ADC = 180°
⇒ ∠1 + ∠2 + 90° = 180°
⇒ ∠1 + ∠2 = 180° – 90°
⇒ ∠1 + ∠2 = 90° …………..(1)
Similary in right ΔACB,
∠2 + ∠3 = 90° ……….(2)
From (1) and (2), we get
∠1 + ∠2 = ∠2 + ∠3
⇒ ∠1 = ∠3.
In ΔADC and ∠CDB
∠1 = ∠3 (proved above)
∠ADC = ∠CDB (each = 90°)
∴ ΔADC ~ ΔCDB
[By AA similarity criterion]
∴ \(\frac{\mathrm{AD}}{\mathrm{CD}}=\frac{\mathrm{CD}}{\mathrm{BD}}\)
⇒ CD2 = BD × AD
Hence Proved

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 14.
ΔABC is a right triangle in which ∠C = 90° and CD ⊥ AB. If BC = a, CA = b, ABC and CD = p, then prove that :
(i) cp = ab
(ii) \(\frac{1}{\mathrm{p}^2}=\frac{1}{\mathrm{a}^2}+\frac{1}{\mathrm{~b}^2}\)
Solution :
(i) Area of right ΔABC
= \(\frac {1}{2}\) base × height
= \(\frac {1}{2}\) a × b
= \(\frac {1}{2}\) ab …(1)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 16
Again, Area of right ΔABC
= \(\frac {1}{2}\) × base × height
= \(\frac {1}{2}\) × c × p
= \(\frac {1}{2}\) × cp …(2)
From (1) and (2), we get
\(\frac {1}{2}\)ab = \(\frac {1}{2}\)cp
⇒ ab = cp
Hence Proved

(ii) In right ΔACB,
AB2 = BC2 + AC2
⇒ c2 = a2 + b2 ……………(3)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 17
Hence Proved

Question 15.
If P and Q are points on sides CA and CB respectively of ΔABC, right angled at C. Prove that (AQ2 + BP2) – (AB2 + PQ2)
Solution :
Given: A right triangle ABC in which ∠C = 90°, P and Q are points on sides CA and CB respectively.
Construction: Join AQ, BP and PQ.
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 18
To prove : AQ2 + BP2 = AB2 + PQ2
Proof : In right ΔACQ. we have
AQ2 = AC2 + QC2 ……………(1)
In right ΔBPC, we have
BP2 = CP2 + BC2 ………………(2)
Adding equ. (1) and (2), we get
AQ2 + BP2 = AC2 + QC2 + CP2 + BC2
= (AC2 + BC2) + (CP2 + QC2)
= AB2 + PQ2
[∵ AC2 + BC2 = AC2 and CP2 + QC2 = PQ2]

Fill in the Blanks

Question 1.
If the basector of an angle of a triangle ………….. the opposite side then triangle is an equilateral triangle.
Solution :
bisects

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 2.
Thales theorem is also known as basic ………
Solution :
proportionality

Question 3.
All equilateral triangles are …………
Solution :
similar

Question 4.
Phythagoras theorem is sometimes also referred to as the ……………. theorem.
Solution :
Baudhayan

Question 5.
If a line divides any two sides of a triangle in the same ………… then line is parallel to the third side.
Solution :
ratio

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 6.
If corresponding angles of two triangles are equal, then they are known as ………….. triangles.
Solution :
equiangular.

Multiple Choice Questions

Question 1.
In equilateral ΔABC, AD is altitude. Then 4AD2 equals.
(a) 2BD2
(b) 2DC2
(c) BC2
(d) 3AB2
Solution :
(d) 3AB2

In ΔADB and ΔADC
AB = AC
∠ADB = ∠ADC
AD = AD
∴ ΔADB ≅ ΔADC
∴ BD = CD (CPCT)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 19
In right ΔADB AB2 = AD2 + BD2
AB2 = AD2 + \(\frac {1}{4}\)AB2
⇒ 4AD2 = 3AB2
So correct choice is (d)

Question 2.
In rhombus PQRS, PQ2 + QR2 + RS2 + SP2 = ?
(a) OP2 + OQ2
(b) OQ2 + OR2
(c) OR2 + OS2
(d) PR2 + QS2
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 20
Solution :
(d) PR2 + QS2

4PQ2 = PR2 + QS2
4QR2 = PR2 + QS2
4RS2 = PR2 + QS2
4PS2 = PR2 + QS2
∴ PQ2 + QR2 + RS2 + PS2 = PR2 + QS2
So correct choice is (d)

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 3.
In figure, DE || BC, AD = 2.4 cm, AE = 3.2 cm, CE = 4.8 cm. The value of BD is :
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 21
(a) 3.6 cm
(b) 4.2 cm
(c) 4.0 cm
(d) None of these.
Solution :
(a) 3.6 cm

Given AD = 2.4 cm
AE = 3.2 cm
EC = 4.8 cm
Let DB = x
We know that \(\frac{\mathrm{AD}}{\mathrm{BD}}=\frac{\mathrm{AE}}{\mathrm{EC}}\)
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 22
Hence correct choice is (a)

Question 4.
In the given figure, ∠BAC = 90° and AD ⊥ BC, then,
[NCERT Exemplar Problems]
(a) BD.CD = AD2
(b) AB.AC = BC2
(c) BC.CD = BC2
(d) AB.AC = AD2
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 23
Solution :
(a) BD.CD = AD2

Since
ΔBDA ~ ΔADC
⇒ \(\frac{\mathrm{BD}}{\mathrm{AD}}=\frac{\mathrm{AD}}{\mathrm{CD}}\)
⇒ AD2 = BD.CD
So correct choice is (a).

HBSE 10th Class Maths Important Questions Chapter 6 Triangles

Question 5.
If ΔABC – ΔEDF and ΔABC is not similar to ADEF, then which of the following is not true?
[NCERT Exemplar Problems]
(a) BC.EF = AC.FD
(b) AB.EF = AC.DE
(c) BC.DE = AB.EF
(d) BC.DE = AB.FD.
Solution :
(c) BC.DE = AB.EF

ΔABC ~ ΔEDF
ΔABC not similar to ΔDEF
ΔABC ~ ΔEDF
HBSE 10th Class Maths Important Questions Chapter 6 Triangles - 24

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HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Haryana State Board HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations Important Questions and Answers.

Haryana Board 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 1.
What is physical and chemical change? List out few examples of both.
Answer:
(A) Physical change:

  • Change in the physical properties of a substance is known as physical change.
  • Colour, shape size, temperature, odour, appearance, etc. are all physical properties. Depending upon the process one or more of these properties may change.

Examples of physical change:
Melting of ice, Heating water, Breaking an object, Dissolving sugar/salt in water, etc.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

(B) Chemical change:
When a substance combines with another substance such that one or more new product is formed through chemical reaction then such a change is called chemical change. In short, chemical change means chemical reaction.
Examples:

  • Souring of milk when it is left at room temperature in summer
  • Rusting of iron tawa or iron items when exposed to a humid atmosphere
  • Fermenting grapes for making wine
  • Cooking food
  • Digestion of food

In all these cases the nature and identity of original substances change due to occurrence of chemical reaction.

Question 2.
How can one find out if a chemical reaction has taken place?
Answer:
If one or more following changes are observed in a process then we can say that a chemical reaction has taken place:

  • Gas has evolved
  • Formation of precipitation
  • Change in colour
  • Change in state
  • Change in temperature

Question 3.
What is a chemical reaction and a chemical equation? How does chemical equation gives idea about atoms, molecules and elements present in it?
Answer:
Chemical reaction :
1. A process in which one or more reactants are chemically. changed into one or more new products is known as a chemical reaction.
2. A chemical equation is the symbolic representation of a chemical reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Chemical equation :
1. The chemical formula of a compound gives the chemical composition of atoms and molecules of the elements present there in.
2. Thus, a chemical equation represents the types of atoms of an element and their numbers present in the compounds involved.

Examples :

  • Water molecule is expressed as H2O. Here, H represents hydrogen whereas O represents oxygen.
  • The subscript 2 of H indicates that H2O is formed from 2 atoms of hydrogen and 1 atom of oxygen.
  • Similarly, CH4 indicates that it is formed from 1 atom of carbon and 4 atoms of hydrogen.

Question 4.
What are reactants and products? Explain with an example.
Answer:
The elements/compounds that undergo chemical reaction are called reactants while those produced during the reaction are called products. Example: When magnesium is burnt in oxygen it gets converted to magnesium oxide.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 1

Question 5.
What is descriptive-equation?
Answer:
An equation described using sentences is called a descriptive-equation or sentence-equation.
Example: When magnesium ribbon is burnt in oxygen, it gets converted to magnesium oxide.

Question 6.
What is a word-equation?
Answer:
1. Writing a chemical equation in the form of words i.e. name of reactants and products is called word-equation.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 2

2. The reactants are written on left hand side (L.H.S.) with plus sign between reactants. Products are written on Right Hand Side (R.H.S.) with a plus sign between products.
3. The arrow head points towards the products and shows the direction of the reaction i.e. formation of products from reactants.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 7.
What is a chemical equation?
Answer:
1. The method of representing a chemical reaction using symbols and formulae of substances involved (i.e. reactants and products) is known as a chemical equation. Example: When a magnesium ribbon is burnt in oxygen, it gets converted to magnesium oxide.

2. Magnesium will be represented as Mg’, oxygen as O2 and magnesium oxide as ‘MgO’. Thus, the chemical equation is:
Mg + O2 → MgO

3. This is just a skeletal chemical equation, It needs to be balanced.
(Note: This chemical equation is unbalanced. The correct chemical equation after balancing would be : Mg + O2 → 2MgO)

Question 8.
What is balancing a chemical-equation? Why is it necessary to balance It?
Answer:
The process of adding atoms to the elements on one or both sides i.e. reactant and product side so that the numbers of atoms of elements on each side becomes equal is known as balancing a chemical equation. Such an equation is called a balanced equation.

Need of balancing:
1. As per the universal law of conservation of mass, mass can neither be created nor destroyed in a chemical reaction. In other words, the total mass of the elements present in the products of chemical reaction should be equal to the total mass of the elements present in the reactants.

2. Now atoms have mass. Hence. in order to fulfill the above condition we need to make sure that the number of atoms in each element remains same on both the sides.
(a) Mg + O2 → MgO Unbalanced. Hence, wrong chemical equation
(b) 2Mg + O2 → 2MgO ….. Balanced. Hence, correct chemical equation

Question 9.
Mention steps for balancing a chemical equation giving an example of reaction of heated iron with steam. Consider the following example:
1. When heated iron metal reacts with steam, it forms iron oxide and hydrogen.
Skeletal equation:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 3

Steps for balancing the above equation:

Step 1:
Take a note of each molecule on left hand side and right hand side and count the number of atoms in each.

Element Present

No. of atoms in reactants (LHS)

No. of atoms in Products (RHS)

Fe

1

3

H

22
O1

4

Step 2:
1. Ideally one should start balancing an equation from the most complex compound Le. the one that has maximum number of atoms. Moreover, one can start balancing from any side i.e. reactant side or product side. In the selected compound, select the element that contains maximum number of atoms.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

2. As we can see here, the most complex compound of the equation is Fe3O4 and the element in it with maximum number of atoms is oxygen. So, we start balancing one equation by first balancing oxygen on L.H.S. and R.H.S.

To balance oxygen atoms:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 4

3. We cannot alter the formulae of a compound to equalize the number of atoms. For example, to balance oxygen atoms we cannot add 4 atoms of oxygen to H2O as H2O4 or (H2O)4 or (H24O).

4. The correct way is to put a co-efficient number to the compound. We take the co-efficient ‘4’ and put in into H2O to make it 4H2O.
The reaction now becomes (To balance hydrogen atoms): Fe + 4H2O → Fe3O4 + H2
(Note that oxygen became 4 in reactant but now hydrogen became 8)

Step 3:
1. Both ‘Fe’ and ‘H’ are unbalanced but, the most complex compound i.e. the compound with highest number of atoms is 4H2O. So we will balance hydrogen atoms first.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 4

The new equation is: Fe + 4H2O → 4 Fe3O4 + 4H2

Step 4:
By looking at the above equation we can see that atoms of all except ‘Fe’ are balanced
To balance Fe:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 6

The final reaction then is : 3Fe + 4H2O → Fe3O4 + 4H2

Step 5:
Finally to check the correctness of the equation balanced, we count atoms of each element on both the sides of the equation.

No. of atomsIn reactants (LHS)In ProductsStatus
Fe33Balanced
H88Balanced
O44Balanced

The equation is now balanced

Step 6:
1. Although the equation is now balanced it does not tells us in which state do reactants react and products emerge. So, the final step involves putting signs of states of elements/compounds involved.
(Note: It is not necessary to show state unless specified.)

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

2. The solid, liquid, aqueous and gaseous forms are represented as (s), (I), (aq) and (g) respectively.
The word aqueous (aq) means a compound is present as solution in water.
The final equation along with states is: 3Fe(S) + 4H2O(g) → Fe3O4(s) + 4H2(g)

3.  In H2O, the symbol (g) is used. This means that water is present in the form of steam.

Question 10.
How can a chemical equation be represented more informatively?
A chemical equation can be made more Informative in following three ways:

(a) By indicating physical state of reactants and products.
We can mention the states of reactants and products namely solid (s), liquid (I), aqueous (aq) and gaseous (g).

Example: Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
(b) By indicating ‘change In heat’ that takes place in the reaction.

Example:
1. When carbon reacts with oxygen, carbon dioxide is formed and heat is released.
C(s) + O2(g) → CO2(g) + Heat
2. In this reaction heat or heat energy is released. Hence, the reaction tells us that burning of carbon in oxygen is an exothermic i.e. heat releasing reaction.

(c) By indicating the conditions under which the reaction takes place.
Sometimes, the reaction takes place under conditions such as sunlight, atmospheric pressure, catalysts. Mentioning such conditions makes a reaction more informative.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Example:
The mixture of carbon monoxide and hydrogen gas is compressed under 300 atmospheric pressure and then passed over a catalyst zinc oxide and chromium oxide and heated to 300°C to form methanol (methyl alcohol)
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 7

Question 11.
Enlist ways of making a chemical equation more informative along with one example of each.
Answer:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 8

Question 12.
Write the skeletal equation for the following reactions:
(i) Hydrogen sulphide reacts with sulphur dioxide to form sulphur and water.
(ii) Methane on burning combines with oxygen to produce carbon dioxide and water.
Answer:
(i) H2S + SO2 → S + H2O
(ii) CH4 + O2 → CO2 + H2O

Question 13.
Balance the following skeletal equations:
(i) BaCl2 + H2SO4 → BaSO4 + HCl
(ii) FeCl2 + H2S → HCl + FeS
(iii) Fe + H2O → Fe3O4 + H2
(iv) NH3 + CuO → Cu + N2 + H2O
Answer:
(i) BaCl2 + H2SO4 → BaSO + 2HCl
(ii) FeCl2 + H2S → 2HCl + FeS
(iii) 3Fe + 4H2O → Fe3O4 + 4H2
(iv) 2NH3 + 3CuO → 3Cu + N2 + 3H2O

Question 14.
It is necessary to balance a chemical reaction. Give reason.
Answer:
1. In a chemical reaction, atoms are neither created nor destroyed but, just exchanged.
2. Thus, the number of atoms of the reactants and products should remain same.
3. Moreover, as per the law of conservation, the chemical equation must be balanced.
4. Hence, it is necessary to balance a chemical reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 15.
Enlist few important types of chemical reactions.
Answer:
Types of chemical reactions:
(1) Combination reaction
(2) Decomposition reaction
(3) Displacement reaction
(4) Double displacement reaction
(5) Oxidation and reduction reaction

Question 16.
What is combination reaction? Explain with the help of example of calcium oxide.
Answer:
Combination reaction:
A reaction in which two or more substances (elements or compounds) combine to form a single substance is called combination reaction.
Example: When calcium oxide and water are mixed, calcium oxide reacts vigorously with water to produce slaked lime (calcium hydroxide) and release a large amount of heat.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 9
Here, calcium oxide and water combined to produce a single product, calcium hydroxide.

Question 17.
State two examples of combination reaction that take place in presence of oxygen.
Answer:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 10

Since oxygen is added in these reactions, these are also called oxidation reactions.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 18.
What is an exothermic reaction? State one example.
Answer:
A chemical reaction in which heat is released (evolved) along with the formation of products is called an exothermic reaction. (Note: Exothermic is not a major type of reaction unlike combination reaction, displacement reaction, etc.)
Example:
(i) Burning of natural gas —

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 11

(ii) Respiration
(iii) Decomposition of vegetable matter into compost.

Question 19.
What is endothermic reaction? Give example.
Answer:
Endothermic reaction: A reaction in which heat is absorbed or say required is called endothermic reaction.
Example: HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 12
When calcium carbonate is supplied heat, calcium oxide and carbon dioxide are formed.

Question 20.
Why is respiration considered exothermic reaction? Explain. OR Explain how food helps in respiration with the help of chemical reaction.
Answer:
1. Food gives us energy which helps us to survive.
2. When we eat food, our body starts digestion process. During digestion the food gets broken into simple substances. For example, carbohydrate present in rice, potato, etc. breaks down to form glucose.
3. The glucose then combines with oxygen present in the body cells and provide energy. This reaction is known as respiration.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 13
Since heat energy is released during respiration, it is known as exothermic reaction.

Question 21.
What is decomposition reaction? State its types.
Answer:
Decomposition reaction :
1. A reaction in which a single reactant (substance) breaks down i.e. decompose to form two or more substances is called decomposition reaction.
2. Decomposition reaction is opposite reaction of combination reaction.
3. To decompose a compound, heat, electric current, light, etc. are supplied during the decomposition reaction.

Type of decomposition reaction:

  • Thermal decomposition,
  • Electrical decomposition,
  • Light decomposition reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 22.
Define thermal decomposition, giving example of lime stone.
Answer:
Thermal decomposition : The decomposition reaction done by supplying heat is known as thermal decomposition reaction.
Example :
When lime stone (calcium carbonate) is heated, it decomposes to give calcium oxide and carbon dioxide.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 14

Question 23.
What is electrical decomposition? Explain with the help of an example.
Answer:
Electrical decomposition reaction (Electrolysis) :
1. The decomposition reaction done by supplying electric current is known as electrical decomposition reaction or electrolysis reaction.

2. For example, by adding one or two drops of sulphuric acid to water and supplying Direct Current (DC) to it, its electrical decomposition takes place and it decomposes into hydrogen and oxygen.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 15
Electrolysis reaction can be studied through an instrument called voltameter.

Question 24.
What happens when silver bromide is exposed to light? OR State and explain light decomposition reaction with the help of an example.
Answer:
1. When silver bromide is exposed to light it decomposes to form silver metal and bromine vapour.

2. The decomposition of silver bromide took place in the presence of light and hence the reaction is light decomposition reaction.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 16

Question 25.
State and explain types of decomposition reaction.
Answer:
Thermal decomposition : The decomposition reaction done by supplying heat is known as thermal decomposition reaction.
Example :
When lime stone (calcium carbonate) is heated, it decomposes to give calcium oxide and carbon dioxide.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 14

Electrical decomposition reaction (Electrolysis) :
1. The decomposition reaction done by supplying electric current is known as electrical decomposition reaction or electrolysis reaction.

2. For example, by adding one or two drops of sulphuric acid to water and supplying Direct Current (DC) to it, its electrical decomposition takes place and it decomposes into hydrogen and oxygen.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 15
Electrolysis reaction can be studied through an instrument called voltameter.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

1. When silver bromide is exposed to light it decomposes to form silver metal and bromine vapour.
2. The decomposition of silver bromide took place in the presence of light and hence the reaction is light decomposition reaction.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 16

Question 26.
What is a displacement reaction? State its types.
Answer:
When a more reactive element displaces (removes) less reactive element from its compound it is called displacement reaction.
Types:
(a) Single displacement reaction (or simply displacement) and (b) Double displacement reaction

Question 27.
What is displacement (or single displacement) reaction? Give two examples.
Answer:
In single displacement reaction, the more reactive element reacts with a compound and takes the place of another element i.e. displaces (or remove) the less reactive element.
Example:
(1) HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 17
Iron is more reactive than copper. Hence, when iron reacts with solution of copper sulphate, it removes (or displaces) copper and gets attached to sulphate.

(2) HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 18
Lead which is more reactive than copper when reacts with copper chloride displaces copper and forms lead chloride.

Question 28.
Explain displacement reaction of zinc with copper sulphate.
Answer:
1. Zinc is more active metal than copper. Hence, when zinc strip is kept in copper sulphate solution, it displaces copper fram copper sulphate and forms zinc sulphate and copper.

2. The blue colour of copper sulphate fades and the solution becomes colourless.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 19

Question 29.
What is double displacement reaction? Give one example.
Answer:
1. A reaction in which two different ions of group of atoms in the reactant molecule are displaced by each other is called double-displacement reaction.

2. A white substance insoluble in water is formed as precipitate and hence the reaction is also called precipitation reaction.
Example:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 20

3. When the aqueous solution of sodium sulphate reacts with aqueous solution of barium chloride a white precipitate of BaSO4 is formed.

4. In this double displacement reaction, sulphate ions \(\mathrm{SO}_4^{2-}\) are displaced by chloride ions Cl and vice-versa. Thus, double displacement shows exchange of ions.

Question 30.
How does ion exchange take place in a double-displacement reaction?
Example:
Answer:
When silver nitrate solution is added to sodium chloride solution, then a white precipitate of silver chloride is formed along with sodium nitrate solution.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 21

Ion exchange:
1. In this reaction, silver ions (Ag+) of silver nitrate react with chloride ions (Cl) of sodium chloride to form a new compound called silver chloride (Ag+Cl or simply AgCl).
2. Sodium ions (Nat) of sodium chloride react with nitrate ions (NO3) of silver nitrate to form sodium nitrate
(Na+NO or NaNO3).

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 31.
State the double displacement reaction of hydrogen sulphide gas with copper sulphate solution.
Answer:
When hydrogen sulphide gas is passed through copper sulphate solution, black precipitate of copper sulphide is formed along with sulphuric acid solution.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 22

Question 32.
Define and very briefly explain oxidation reaction, reduction reaction and redox reaction.
Answer:
Oxidation reaction :
In a chemical reaction, if oxygen is added to or hydrogen is removed from an element, molecule or a compound, it is called an oxidation reaction.

Reduction:

  • To every oxidation reaction, simultaneously there occurs a reduction reaction.
  • The opposite reaction of oxidation reaction in which hydrogen is added to or oxygen is removed from an element, molecule or a compound is called reduction.

Redox:
In a redox reaction, oxidation and reduction reactions take place simultaneously. Hence, the entire reaction is called Redox (Red = reduction, ox = oxidation) reaction.

Oxidation and reduction can be understood with a simple table:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 23

Question 33.
What is a redox reaction? Explain with examples. OR Explain briefly oxidation and reduction reactions.
Answer:
Oxidation reaction :
In a chemical reaction, if oxygen is added to or hydrogen is removed from an element, molecule or a compound, it is called an oxidation reaction.
For Example:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 24

In this reaction, oxygen is added and so hydrogen gets oxidized. Hence, it is an oxidation reaction.

Reduction reaction :

  • To every oxidation reaction, simultaneously there occurs a reduction reaction.
  • The opposite reaction of oxidation reaction n which hydrogen is added to or oxygen is removed from an element, molecule or a compound is called reduction.

For Example:

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 26

In this reaction, oxygen is removed from CuO and so it is a reduction reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Redox reaction:
Since reduction reaction and oxidation occur simultaneously, the reaction is called redox
(Note: Reduction Red and Oxidation = Ox. Thus, redox reaction.)
For Example:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 27
In this reaction —

  • HO is formed from H2 Since H2 got added to Oxygen O. So it is an oxidation reaction,
  • CuO got converted into Cu because oxygen got removed and so it is reduction reaction.
  • Since oxidation and reduction have taken place simultaneously, this whole reaction is called a redox reaction.

Question 34.
State two redox reactions.
ZnO + C → Zn + CO
MnO2 + 4HCl → MnCl2 + 2H2O + Cl2
In first reaction carbon is oxidized to CO and ZnO is reduced to Zn. In second reaction HCl is oxidized to Cl2 whereas MnO2 is reduced to MnCl2.

Question 35.
Define different types of chemical reactions and give one example of each.
Answer:
Types of chemical reactions:
1. Combination reaction:
A reaction in which two or more substances (elements or compounds) combine to form a single substance is called combination reaction.

Example:
When calcium oxide and water are mixed, calcium oxide reacts vigorously with water to produce slaked lime (calcium hydroxide) and release a large amount of heat.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 28

2. Decomposition reaction: A reaction in which a single reactant (substance) breaks down i.e. decompose to form two or more substances is called decomposition reaction.

Types:
(a) Thermal decomposition :
Example: When lime stone (calcium carbonate) is heated, it decomposes to give calcium oxide and carbon dioxide.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 29

(b) Electrical decomposition reaction (Electrolysis) :
Example: Adding one or two drops of sulphuric acid to water and supplying Direct Current (DC) to it, its electrical decomposition takes place and it decomposes into hydrogen and oxygen.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 30

(c) Light decomposition reaction:
Example: When silver bromide is exposed to light it decomposes to form silver metal and bromine vapour.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 31

3. Displacement reaction:
When a more reactive element displaces (removes) less reactive element from its compound it is called displacement reaction.

Types:
(a) Single displacement reaction (or simply displacement):

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 34
Iron is more reactive than copper. Hence, when iron reacts with solution of copper sulphate, it removes (or displaces) copper and gets attached to sulphate.

(b) Double displacement reaction:
Example:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 35

When the aqueous solution of sodium sulphate reacts with aqueous solution of barium chloride a white precipitate of BaSO4 is formed.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

4. Redox reaction:
The reaction in which reduction reaction and oxidation reaction occur simultaneously is called redox reaction
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 36

Question 36.
What is corrosion? Write a brief note.
Answer:
1. When a metal comes in contact with humid air, moisture or a chemical such as acid, the surface of metal starts getting eaten up. This is called corrosion.
2. Corrosion is mainly caused by the oxidation of metals in humid air. Rusting of iron is the most common form of corrosion.
3. Due to corrosion, silver ornaments become black and a green coating gets deposited on copper vessels.
4. Corrosion damages vehicles, bridges, iron rails, ships and other metal structures.
5. Corrosion of iron is a serious problem. It causes huge sum to be spent on maintaining iron structures and replacing corroded parts.

Question 37.
What is rancidity?
Answer:
1. Oxidation affects food that contains fats and oils.
2. When food items (such as snacks like pun, chakni, chavana, etc) prepared using fat and oils are kept for longer period, they develop an unpleasant smell and taste. We then say that the food item has become rancid.
3. One can reduce the rate of rancidity by keeping the food items in air-tight containers. This, slows down oxidation of food.
4. Packets of chips are flushed with nitrogen to prevent chips from becoming rancid.

Question 38.
Explain the following terms with one example each. (a) Corrosion, (b) Rancidity.
Answer:
Types of chemical reactions:
1. Combination reaction:
A reaction in which two or more substances (elements or compounds) combine to form a single substance is called combination reaction.

Example:
When calcium oxide and water are mixed, calcium oxide reacts vigorously with water to produce slaked lime (calcium hydroxide) and release a large amount of heat.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 28

2. Decomposition reaction: A reaction in which a single reactant (substance) breaks down i.e. decompose to form two or more substances is called decomposition reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Types:
(a) Thermal decomposition :
Example: When lime stone (calcium carbonate) is heated, it decomposes to give calcium oxide and carbon dioxide.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 29

(b) Electrical decomposition reaction (Electrolysis) :
Example: Adding one or two drops of sulphuric acid to water and supplying Direct Current (DC) to it, its electrical decomposition takes place and it decomposes into hydrogen and oxygen.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 30

(c) Light decomposition reaction:
Example: When silver bromide is exposed to light it decomposes to form silver metal and bromine vapour.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 31

3. Displacement reaction: When a more reactive element displaces (removes) less reactive element from its compound it is called displacement reaction.

Types:
(a) Single displacement reaction (or simply displacement):

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 34
Iron is more reactive than copper. Hence, when iron reacts with solution of copper sulphate, it removes (or displaces) copper and gets attached to sulphate.

(b) Double displacement reaction:
Example:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 35

When the aqueous solution of sodium sulphate reacts with aqueous solution of barium chloride a white precipitate of BaSO4 is formed.

4. Redox reaction:
The reaction in which reduction reaction and oxidation reaction occur simultaneously is called redox reaction
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 36

1. When a metal comes in contact with humid air, moisture or a chemical such as acid, the surface of metal starts getting eaten up. This is called corrosion.
2. Corrosion is mainly caused by the oxidation of metals in humid air. Rusting of iron is the most common form of corrosion.
3. Due to corrosion, silver ornaments become black and a green coating gets deposited on copper vessels.
4. Corrosion damages vehicles, bridges, iron rails, ships and other metal structures.
5. Corrosion of iron is a serious problem. It causes huge sum to be spent on maintaining iron structures and replacing corroded parts.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 39.
Differentiate between exothermic reaction and endothermic reaction.

Exothermic reaction

Endothermic reaction

1. A chemical reaction in which heat is released (evolved) along with the formation of products is called an exothermic reaction.
2. For example, burning of natural gas, respiration, etc.
1. A reaction in which heat is absorbed or say required is called endothermic reaction.
2. For example, reaction of calcium oxide with water.

Question 40.
Give examples of each characteristic change that determine occurrence of a chemical reaction.

ExampleChange in characteristic
1. When zinc reacts with sulphuric acid, bubbles of hydrogen gas are produced.Here, gas has evolved. Also, temperature rises.
2. Adding potassium iodide solution to solution of lead nitrate forms a yellow precipitate of lead iodideFormation of precipitation. Also, colour changes to yellow
3. When citric acid is added to purple coloured potassium permanganate, the solution becomes colourless.Change in colour
4. When water is added to quick lime, slaked lime is formed and a lot of heat energy is released.Change in temperature
5. Burning of candle wax produces water and carbon dioxideChange in state of substance from solid to liquid when it undergoes combustion reaction.

Question 41.
Balance the following equations.
KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2
Balanced equation:
2KMnO4+ 16HCl → 2KCl + 2MnCl2 + 8H4O(l)  + 5Cl2

Question 42.
Explain how calcium oxide gets converted into slaked lime and how slaked lime gets converted  into calcium carbonate?
Answer:
1. When calcium oxide or say quick lime (CaO) is dissolved in water, solution of calcium hydroxide i.e. slaked lime (Ca(OH)2) is produced.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 37

2. Calcium hydroxide is filtered and the filtered solution is applied to the walls as white wash.

3. On applying to the walls, calcium hydroxide reacts with the carbon dioxide (CO2) of the air and forms insoluble white thin layer of calcium carbonate (CaCO3) on the walls.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 40

Question 43.
What happens when carbon dioxide and water react in the same ratio?
Answer:
When six molecules of carbon dioxide and six molecules of water undergo reaction, glucose is formed along with with evolution of oxygen gas.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 39

Question 44.
State the respiration reaction.
Answer:
When food glucose. combines with oxygen present in the body cells, it gives energy to the body through respiration process.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 41

Question 45.
State the decomposition reaction of sodium chloride. OR State the electrolysis reaction of sodium chloride.
Answer:
When electric current is passed through molten sodium chloride, it undergoes electrolysis and decomposes into sodium metal and chlorine gas.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 42

Question 46.
What happens when lead is placed in copper chloride solution?
Answer:
When a strip of lead (Pb) is p)aced in copper chloride (CuCl2) solution, more active lead displaces copper from the solution.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 43

Question 47.
Magnesium is a reactive metal. What will happen if you put it in hydrochloric acid solution?
Answer:
Magnesium metal will react with hydrochloric acid to form magnesium chloride and hydrogen gas.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 44
In this displacement reaction, magnesium displaces hydrogen from hydrochloric acid solution. This displacement reaction occurs because magnesium is more reactive than hydrogen.

Question 48.
How can the black coating of copper oxide be removed chemically?
Answer:
The black coating of copper oxide can be removed chemically by passing hydrogen gas over heated copper oxide. The black coating will turn brown in colour since oxygen will be removed by hydrogen.
CuO+H2 → Cu+H2O

Question 49.
State the ascending order of reactivity for metals Cu, Ag and Fe on the basis of reactions given below:
Answer:
(i) Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
(ii) Cu(s) + FeSO4(aq) → No reaction
(iii) Cu(s) + 2AgNO3(aq) → Cu(NO3)(aq) + 2Ag(s)
(iv) 2Ag(s) + Cu(NO3)2 → No reaction
Based on the given reactions, ascending order of reactivity of Cu, Ag and Fe is – Ag < Cu < Fe

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 50.
State the reaction when iron (III) oxide is heated with aluminum powder. Also state the type of reaction.
Answer:
When iron (III) oxide is heated with aluminium powder, aluminium oxide and iron metal is formed.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 45
This is a displacement reaction. In this displacement reaction, a more reactive metal, aluminium displaces a less reactive metal, iron, from its oxide, iron (III) oxide.

Question 51.
Three test tubes are taken and marked as ‘X’, ‘Y’ and ‘Z’. In test tube X, iron nail is dipped in water. In test tube Y, Iron nail is dipped in mixture of water and oil. In test tube Z, iron nail is added with dry CaCl2. In which test tube, the iron nail will rust? Why?
Answer:
The iron nail which is dipped in test-tube containing water i.e. test-tube X will rust.
Reason: It is a property of iron that when it comes in contact of moisture it starts rusting.

Question 52.
Why do most of the metal articles become dull, when left in open air?
Answer:
Metal articles left in an open air reacts with the gases or say the air of atmosphere. Such metals then form a layer of oxide compound on their surface. This makes the metal lose their luster and become dull.

Question 53.
Why is photosynthesis considered as an endothermic reaction?
Answer:
1. An endothermic reaction is one which requires energy to occur.
2. In photosynthesis reaction, sunlight acts as an energy. Plants use this energy to form glucose from carbon dioxide and water. Hence, this reaction is called an endothermic reaction.

Question 54.
When the guests arrived at Mrs. Sudha Murthy’s house her daughter Nitya got very excited.
Answer:
She offered lemonade to the guests to which they agreed. Nitya went into kitchen and gathered ingredients such as lemon, sugar, water, salt, etc. and started preparing the lemonade in a large copper vessel. When Mrs. Murthy came to kitchen she stopped Nitya from using a copper vessel and asked to use a steel vessel. Why do you think she asked Nitya to do so?

  • Lemon is acidic in nature, It contains citric acid.
  • Although citric acid of lemon does not cause any harm but when it is put in vessel made of copper, it starts reacting with copper. This causes copper-poisoning in human body which leads to gastro-intestinal problems.
  • Here, Nityas mother displayed value of awareness and concern about social health.

Question 55.
A student mixed solutions of lead (II) nitrate and potassium Iodide.
(a) Can you tell the colour of precipitate formed?
(b) Which type of chemical reaction is this? Provide your reason.
Answer:
(a) The precipitate formed is of yellow colour.
(b) The reaction is as follows:
Pb(NO3)2 + 2Kl → 2Pbl2 + KNO3
In the reaction, lead and potassium exchange their Ions and hence the reaction is a double displacement reaction.

Question 56.
Ritesh had a blue coloured salt in test-tube. The teacher did not tell the name of the salt. The teacher asked Ritesh to heat the salt. On heating it became white. Then the teacher asked him to add water, The salt again turned blue. Which salt did Ritesh have in the test-tube? State the reason for changes in colour.
Answer:
1. The substance is copper sulphate (CuSO2 . 5H2O). It is blue in colour.
2. On heating it loses water and so what remains is white coloured CUSO4.
3. On adding water it again becomes hydrated and regains blue colour.

Question 57.
Complete the missing components/variables given as x and y in the following reactions.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 46
Answer:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 47

Question 58.
Identify the reducing agent in the following reactions.
(a) 4NH3 + 5O2 → 4NO + 6H2O
(b) H2O + F2 → HF + HOF
Answer:
(a) In this reaction, NH3 is the reducing agent because it gives hydrogen and gets oxidized to NO.
(b) H2O is the reducing agent because the electronegative F gets added and so H2O gets oxidized to HOF.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 59.
Identify the oxidizing agent (oxidant) in the following reactions.
(a) Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H2O
(b) 2Mg + O2 → 2MgO
Answer:
(a) HCl has been oxidized to Cl2 (Removal of H) and Pb3O4 has been reduced to PbCl2 (Removal of O). Hence, Pb3O4 is the oxidizing agent (oxidant).
(b) Mg has been oxidized to MgO (Addition of oxygen O). Hence, O2 is the oxidant.

Question 60.
Grapes hanging on the plant do not ferment but after being plucked from the plant can be fermented. Under what conditions do these grapes ferment? Is It a chemical or a physical change?
Answer:
1. When grapes are attached to the plant, they receive oxygen right upto the cell level. As a result, they undergo aerobic respiration and do not ferment.
2. When grapes are plucked, the oxygen does not reach the cell level and so the aerobic respiration does not occur.
3. Fermentation takes place only in the absence of oxygen I.e. under anaerobic condition. As a result, grapes start fermenting after being plucked.

Question 61.
During the reaction of some metals with dilute hydrochloric acid, following observations were made.
(A) Silver metal does not show any change
(B) The temperature of the reaction mixture rises when aluminium (Al) is added.
(C) The reaction of sodium metal is found to be highly explosive
(D) Some bubbles of a gas are seen when lead (Pb) is reacted with the acid
Explain these observations giving suitable reasons.
Answer:
(a) In the reactivity series, silver lies below hydrogen which means silver is less reactive than hydrogen. So, silver cannot displace hydrogen when reacted with acid.

(b) The reaction of Al with dilute HCl is exothermic i.e., heat is produced in the reaction. As a result, the temperature of the reaction mixture rises. The reaction is as follows.
2Al + 6HCl → 2AlCl3 + 3H2 + Heat

(c) Sodium is a very reactive metal. It reacts explosively (extremely rapidly) with hydrochloric acid to form sodium chloride and hydrogen along with the evolution of heat. H2 gas produced catches fire immediately.

(d) Lead is present just above the hydrogen in the activity series of metals. Hence, it is slightly more reactive and displaces hydrogen from acid very slowly that too upto a small extent. Hence, only bubbles of H2 are seen to be evolved.

Question 62.
Why do we store silver chloride in dark coloured bottles?
Answer:
Dark coloured bottles interrupt the path of light and prevent them from directly entering into the bottles. Storing silver chloride in dark coloured bottles does not allow the light to reach silver chloride in the bottles. This prevents its decomposition. If the silver chloride is not stored in dark bottles, the following reaction would take place.
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 48

Question 63.
A magnesium ribbon Is burnt in oxygen to give a white compound X accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitrogen, it continues to burn and forms a compound Y.
(A) Write the chemical formulae of X and Y.
(B) Write a balanced chemical equation, when X is dissolved in water.
Answer:
The reaction for the first statement is:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 49
(A) The chemical formulae of X and Y are: X = MgO; Y = Mg3N2
(B)
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 50

Very Short Answer Type Questions

Question 1.
What is physical change?
Answer:
Change in the physical properties of a substance is known as physical change.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 2.
What can change under physical change?
Answer:
Colour, shape, temperature, appearance or odour.

Question 3.
Give few examples of physical change.
Answer:
Melting of ice, heating water, breaking an object, dissolving sugar/salt in water.

Question 4.
What is chemical change?
Answer:
When a substance combines with another substance such that one or more new product is formed it is called chemical change. In short, chemical change is chemical reaction.

Question 5.
Give two examples of chemical change.
Answer:
(a) Rusting if iron,
(b) Souring of milk when it is left at room temperature for long.

Question 6.
Define reactants and products.
Answer:
The substances that undergo chemical reaction are called reactants while those produced during the reaction are called products.

Question 7.
What is word equation?
Answer:
Writing a chemical equation in the form of words i.e. name of reactants and products is called word-equation.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 8.
State one example of word equation.
Answer:
Hydrogen + chlorine = Hydrochloric acid

Question 9.
Define chemical equation.
Answer:
The method of representing a chemical reaction using symbols and formulae of substances involved (i.e. reactants and products) is known as a chemical equation.

Question 10.
State the law of conservation of mass.
Answer:
In a chemical reaction, mass can neither be created nor be destroyed. The total mass in the universe remains constant.

Question 11.
Write skeletal equation for: When heated iron metal reacts with steam, it forms iron oxide and hydrogen.
Answer:
Fe + H2O → Fe3O4 + H2

Question 12.
When you burn a silvery-white metal P, it burns with dazzling flame and produces white powder Q. What Is metal P and what is powder Q.
Answer:
Metal P is magnesium and white powder is magnesium oxide.

Question 13.
A chemical equation states 200 atm. on the arrow between LHS and RHS what does it mean?
Answer:
It means the reaction took place under 200 atmospheric pressure.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 14.
What is a catalyst?
Answer:
A substance that increases the rate of reaction without itself undergoing any permanent change is called a catalyst. For example, sunlight.

Question 15.
Match the following:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 51
Answer:
(a – ii) (b – iv) (c – i) (d – iii)

Question 16.
Write the balanced chemical equation for the following:
Answer:
The mixture of carbon monoxide and hydrogen gas is compressed under 300 atmospheric pressure and then passed over a catalyst zinc oxide and chromium oxide heated to 300°C to form methanol (methyl alcohol)

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 52

Question 17.
What is a combination reaction?
Answer:
A reaction in which two or more substances combine to form a single substance is called combination reaction.

Question 18.
Balance: MnO2 + HCl → MnCl2 + Cl2 + H2O
Answer:
4 MnO2 + 4HCl → MnCl2 + Cl2 + 2H2O

Question 19.
Define exothermic reaction.
Answer:
A chemical reaction in which heat is released along with the formation of products is called an exothermic reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 20.
State a chemical reaction for exothermic reaction.
Answer:
Burning of natural gas:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 53

Question 21.
What is endothermic reaction?
Answer:
A reaction in which heat is absorbed or say required is called endothermic reaction.

Question 22.
Give an equation showing endothermic reaction.
Answer:
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 54

Question 23.
Classify the following chemical reactions into endothermic and exothermic.
(i) Electrolysis of water,
(ii) Burning of natural gas,
(iii) Decomposition of calcium carbonate and
(iv) Burning of magnesium ribbon in air.
Answer:
Exothermic reaction: (ii) and (iv),
Endothermic reaction: (I) and (iii)

Question 24.
Why does the colour of copper sulphate change when an ¡ron nail is dipped in it?
Answer:
Iron displaces copper from CuSO4 to form FeSO4 which is pale green in colour. Hence,

Question 25.
Define decomposition reaction.
Answer:
A reaction in which a compound splits into two or more simpler substances is called decomposition reaction.

Question 26.
State the types of decomposition reaction.
Answer:
(a) Electrical decomposition
(b) Thermal decomposition and
(c) Light decomposition.

Question 27.
When a white salt is heated it decomposes to produce brown fumes. Which is this salt?
Answer:
Lead nitrate Pb(NO3)2

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 28.
If you strongly heat iron salt, its colour changes to brown along with emitting smell like burning of sulphur.
(a) What is the iron salt?
(b) Which type of reaction is this?
Answer:
(a) Ferrous sulphate
(b) Decomposition.

Question 29.
If you burn hydrogen in the presence of oxygen it will give water whereas if you electrolyse water it will give out hydrogen and oxygen.
(a) Which type of reaction takes place in first situation?
(b) Which type of reaction takes place in second situation?
Answer:
(a) Combination
(b) displacement.

Question 30.
What is formed when silver bromide is exposed to light?
Answer:
Silver metal and bromine vapour.

Question 31.
What is displacement reaction?
Answer:
The reaction in which a more reactive metal displaces the less reactive (or active) metal from its salt solution is called displacement reaction.

Question 32.
State chemical equation for;
(a) Iron reacting with steam,
(b) Magnesium reacting with dilute hydrochloric acid.
Answer:
(a) 3Fe + 4H2O → Fe3O4 + 4H2
(b) Mg + 2HCl → MgCl + H2

Question 33.
Look at the chemical equation.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations 55
(i) Identity ‘X’ and ‘Y’,
(ii) What type of reaction is this?
Answer:
(i) ‘X’ is Na2SO4 and ‘Y’ is BaSO4,
(ii) It is a double displacement as well as a precipitate reaction.

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 34.
What is double displacement reaction?
Answer:
A chemical reaction in which two compounds react by an exchange of ions to form two new compounds is called double displacement reaction.

Question 35.
Look at reaction and state what is more reactive, ‘Mn’ or ‘Al’ and why.
3MnO2 + Al → 3Mn + 2Al2O3
Answer:
‘Al’ is more reactive than ‘Mn’ since ‘Al’ displaces ‘Mn’ from its oxide.

Question 36.
What is ion exchange?
Answer:
The process in which ions of one substance are replaced by similarly charged ions or another substance is called ion exchange.

Question 37.
Define oxidation reaction.
Answer:
The chemical reaction in which oxygen is added to a substance or hydrogen is removed from a substance is called oxidation.

Question 38.
What is reduction reaction?
Answer:
The reaction in which hydrogen is added to a substance or oxygen is removed from a1 substance is called reduction.

Question 39.
Why redox reaction Is called so?
Answer:
In redox reaction, oxidation as well as reduction occurs simultaneously. Hence, the reaction is called redox (reduction oxidation) reaction.

Question 40.
Give redox reaction when hydrogen suiphide reacts with chlorine.
Answer:
H2S+Cl2 → S+2HCl

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 41.
Give the redox reaction when zinc oxide Is heated with carbon.
Answer:
ZnO+C → Zn+CO

Question 42.
What is oxidized and what is reduced in the following equation?
SO2 + 2H2S → 3S + 2H2O
Answer:
SO2 changes to S i.e; oxygen is reduced. H2S changes to S i.e. hydrogen is removed through oxidation.

Question 43.
State two common effects of oxidation in daily life.
Answer:
Oxidation causes
(a) Corrosion of metals and
(b) Rancidity in food.

Question 44.
What is corrosion?
Answer:
When a metal comes in contact of humid air, moisture or a chemical such as acid,the surface of metal starts getting eatenup.
This is called corrosion.

Question 45.
Give two examples of corrosion.
Answer:
(a) Silver ornaments turn black and
(b) Green coating gets deposited on copper vessel.

Question 46.
Give a chemical reaction showing rusting of iron.
Answer:
4Fe + 3O2 + 2xH2O → 2Fe2O3 x H2O
(Note: Here ‘x’ indicates the number of molecules of water and it keeps on varying.)

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 47.
What is rancidity?
Answer:
The condition where in due to oxidation of fatty and oily foods such as snacks the food develops unpleasant smell and taste is called rancidity.

Fill in the Blanks

1. Formation of …………… is a proof as well as one of the indicators of chemical reaction.
Answer:
Precipitation

2. The characteristic of ………………. is observed to assure occurrence of chemical reaction when citric acid is added to potassium permanganate.
Answer:
Change in colour

3. Matter can neither be created, nor be destroyed. It is called the law of ………………
Answer:
conservation of mass.

4. On adding solution of substance ‘X’ to solution of ‘KI’, a yellow solid separates out from the solution. Now answer the two questions. (a) The substance ‘X’ is , (b) The solid yellow substance is ………………..
Answer: (a) Lead nitrate, (b) Lead iodide

5. Balancing in equation should be started from ………………
Answer:
The most complex substance in the reaction.

6. The reaction 2AgBr → 2Ag + Br2 is used in ……………
Answer:
Black and white photography.

7. ……………………. is formed when iron is heated with sulphur.
Answer:
Iron suiphide

8. Calcium oxide reacting vigorously with water to form slaked like is a type of ………………….. reaction.
Answer:
Combination

9. ………………….. is a more reactive metal among Fe and Mg.
Answer:
Mg

10. Formula for ferrous sulphate crystals is………………..
Answer:
FeSO2 . 7H2O

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

11. On passing electric current through water, ………………….. is/are obtained.
Answer:
Hydrogen and oxygen

12. Silver chloride when exposed to sunlight turns
Answer:
Grey

13. Hydrogen gas burns rapidly with sound.
Answer:
Popping

14. On submerging iron nail in copper sulphate solution the nail turns coloured.
Answer:
Reddish-brown

15. Generally, the double displacement reaction takes place in
Answer:
Solutions

16. Packets of chips are flushed with to prevent rancidity.
Answer:
Nitrogen

True Or False

1. ‘Respiration is an endothermic reaction’. — False.
2. ‘Adding potassium iodide to solution of lead nitrate gives green precipitate of lead iodide’. — False.
3. ‘Descriptive equation = Word equation’. — False
4. ‘It is mandatory to write physical states in chemical equation’. — False
5. ‘A decomposition reaction is similar to combination reaction’. — False
6. ‘Ferric oxide formed due to decomposition of ferrous sulphate is obtained in liquid state’. — False
7. During electrolysis of water, the volume of gas collected on negative electrode is same as the volume of gas collected on the positive electrode. — False
8. In reaction, \(\mathrm{MnO}_4^{2-} \rightarrow \mathrm{MnO}_2+\mathrm{MnO}_4^{1-}\mathrm{MnO}_4{ }^{2-}\) acts both as oxidizing agent as well as reducing agent. —  True
9. In a double displacement reaction, one of the insoluble product precipitates. — True
10. The major cause of corrosion is hydrogenation. — False
11. Lime stone (CaCO3) decomposes on heating with evolution of CO2. — True
12. Calcium hydroxide combines slowly with oxygen present in air to form a white layer of calcium carbonate on the wall. — False
13. Among the following reactions only reaction number (ii) is a double displacement reaction.
(i) Pb + CuCl2 → PbCl2 + Cu
(ii) Na2SO4 + BaCl2 → BaSO4 + 2NaCl
(iii) C + O2 → CO2
(iv) CH4 + 2O2 → CO2 + 2H2O — True
HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations
14. Exposure of silver chloride to sunlight for a long duration turns it grey due to the formation of silver by decomposition of silver chloride. — True
15 The proportion by volume of H2 and O2 gases obtained t electrodes during electrolysis of water is 1 :1. — False
16. Precipitate obtained in precipitation reaction is soluble in water. — True
17. An element X when exposed to moist air turns reddish brown giving rise to a new compound Y. Here, X is Fe and Y is Fe2O3. — True
18. When lead (II) nitrate decomposes it produces lead (II) oxide, nitrogen dioxide and oxygen gas. In the balanced equation the value of co-officient of nitrogen dioxide is 4. — True
19. You cannot perform an oxidation reaction without a simultaneous reduction reaction. — True

Match the Following:

Question 1.

A

B

1. Formation of iron sulphate and copper from iron and copper sulphate

a. Decomposition reaction
2. Formation of water from H2 and O2

b. Combination reaction

3. Formation of ferric oxide, sulphur dioxode from ferrous sulphate

c. Displacement reaction

Answer: (1-c), (2-b), (3-a)

HBSE 10th Class Science Important Questions Chapter 1 Chemical Reactions and Equations

Question 2.

A

B

1. Copper sulphate

a. Blue

2. Ferrous sulphate

b. Green

3. Barium sulphate

Answer: (1-a), (2-b)

Question 3.

1. Iron nail dipped in copper sulphatea. Turns grey
2. Silver chloride kept in China dish under sunlightb. Turns brown
c. Turns faded blue

Answer: (1-a) ,(2-b)

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